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Page title matches

• 1995 AHSME Problems/Problem 15
  1 KB (183 words) - 21:54, 2 August 2016
• 2002 AMC 10A Problems/Problem 15
  993 bytes (147 words) - 01:50, 26 January 2018
• 2002 AMC 10B Problems/Problem 15
  45 bytes (5 words) - 18:14, 28 July 2011
• 2000 AMC 10 Problems/Problem 15
  45 bytes (4 words) - 23:54, 26 November 2011
• 1985 AJHSME Problems/Problem 15
  2 KB (245 words) - 17:03, 17 June 2024
• 1986 AJHSME Problems/Problem 15
  1 KB (155 words) - 15:32, 9 November 2017
• 2002 AMC 12A Problems/Problem 15
  {{duplicate|[[2002 AMC 12A Problems|2002 AMC 12A #15]] and [[2002 AMC 10A Problems|2002 AMC 10A #21]]}} \text{(E) }15
  3 KB (519 words) - 21:34, 23 June 2023
• 2004 AMC 12B Problems/Problem 15
  {{duplicate|[[2004 AMC 12B Problems|2004 AMC 12B #15]] and [[2004 AMC 10B Problems|2004 AMC 10B #17]]}}
  2 KB (326 words) - 09:47, 17 October 2020
• 2004 AMC 10B Problems/Problem 15
  <math> \textbf{(A)}\ \textdollar 1.15\qquad\textbf{(B)}\ \textdollar 1.20\qquad\textbf{(C)}\ \textdollar 1.25\qqu .../math>. Her coins are worth <math>200-5n=\boxed{\mathrm{(A)\ }\textdollar1.15}</math>.
  1 KB (220 words) - 00:53, 24 July 2014
• 2009 AMC 12A Problems/Problem 15
  4 KB (634 words) - 16:34, 3 December 2020
• 2001 AMC 12 Problems/Problem 15
  1 KB (225 words) - 15:26, 30 November 2021
• 2009 AMC 10B Problems/Problem 15
  {{duplicate|[[2009 AMC 10B Problems|2009 AMC 10B #15]] and [[2009 AMC 12B Problems|2009 AMC 12B #8]]}}
  3 KB (545 words) - 13:37, 3 September 2023
• 2009 AMC 12B Problems/Problem 15
  2 KB (336 words) - 16:58, 27 December 2020
• 1987 AJHSME Problems/Problem 15
  731 bytes (110 words) - 16:40, 30 July 2023
• 2009 AIME I Problems/Problem 15
  .../math> and <math>COP</math>, with <math>BO=CO=7</math> and <math>OP=7 \tan 15=7(2-\sqrt{3})=14-7\sqrt3</math>. Then, the area of [<math>\triangle BPC</ma
  6 KB (1,048 words) - 19:35, 2 January 2023
• 1988 AJHSME Problems/Problem 15
  721 bytes (100 words) - 23:55, 4 July 2013
• 2009 AIME II Problems/Problem 15
  11 KB (1,862 words) - 21:23, 23 May 2024
• 1989 AJHSME Problems/Problem 15
  1 KB (194 words) - 00:03, 5 July 2013
• 1990 AJHSME Problems/Problem 15
  863 bytes (124 words) - 00:06, 5 July 2013
• 1991 AJHSME Problems/Problem 15
  draw((1,0)--(1+9*sqrt(3)/2,9/2)--(1+9*sqrt(3)/2,15/2)--(1+5*sqrt(3)/2,11/2)--(1+5*sqrt(3)/2,9/2)--(1+2*sqrt(3),4)--(1+2*sqrt(3 draw((1+9*sqrt(3)/2,15/2)--(9*sqrt(3)/2,15/2)--(5*sqrt(3)/2,11/2)--(5*sqrt(3)/2,5));
  1 KB (197 words) - 00:07, 5 July 2013

Page text matches

• 2006 AIME I Problems/Problem 4
  ...> have a factor of <math>10</math>. <math>86</math> have a factor of <math>15</math>. And so on. This gives us an initial count of <math>96 + 91 + 86 + \
  2 KB (278 words) - 08:33, 4 November 2022
• 2006 AIME I Problems/Problem 3
  ...ber after digit removal could be 10,20,30) or <math>c=5.</math> Testing 5, 15, and 25 as the numbers after removal we find that our answer is clearly <ma
  4 KB (622 words) - 03:53, 10 December 2022
• 2021 JMC 10
  ...f{(A) } 5 \qquad\textbf{(B) } 9 \qquad\textbf{(C) } 12 \qquad\textbf{(D) } 15 \qquad\textbf{(E) } 16</math> ...e written with digits in reverse order. A citizen in Malachar writes <math>15\cdot 73.</math> What does this Malacharian write as the answer?
  12 KB (1,784 words) - 16:49, 1 April 2021
• 2006 AMC 12B Problems
  \text {(A) } 5 \qquad \text {(B) } 10 \qquad \text {(C) } 15 \qquad \text {(D) } 20 \qquad \text {(E) } 25 ...three times as long as a second side, and the length of the third side is 15. What is the greatest possible perimeter of the triangle?
  13 KB (2,058 words) - 12:36, 4 July 2023
• 2006 AMC 12A
  * [[2006 AMC 12A Problems/Problem 15]]
  1 KB (168 words) - 21:51, 6 October 2014
• 2004 AMC 12A
  * [[2004 AMC 12A Problems/Problem 15]]
  2 KB (186 words) - 17:35, 16 December 2019
• 2004 AMC 12B
  * [[2004 AMC 12B Problems/Problem 15]]
  2 KB (181 words) - 21:40, 6 October 2014
• 2005 AMC 12A
  ** [[2005 AMC 12A Problems/Problem 15|Problem 15]]
  2 KB (202 words) - 21:30, 6 October 2014
• 2005 AMC 12B
  * [[2005 AMC 12B Problems/Problem 15|Problem 15]]
  2 KB (206 words) - 23:23, 21 June 2021
• 2000 AMC 12
  * [[2000 AMC 12 Problems/Problem 15]]
  1 KB (126 words) - 13:28, 20 February 2020
• 2001 AMC 12
  * [[2001 AMC 12 Problems/Problem 15]]
  1 KB (127 words) - 21:36, 6 October 2014
• 2002 AMC 12A
  * [[2002 AMC 12A Problems/Problem 15]]
  1 KB (158 words) - 21:33, 6 October 2014
• 2003 AMC 12A
  * [[2003 AMC 12A Problems/Problem 15]]
  1 KB (162 words) - 21:52, 6 October 2014
• 2002 AMC 12B
  * [[2002 AMC 12B Problems/Problem 15]]
  1 KB (154 words) - 00:32, 7 October 2014
• 2003 AMC 12B
  * [[2003 AMC 12B Problems/Problem 15]]
  1 KB (160 words) - 20:46, 1 February 2016
• 2006 AMC 12A Problems
  <math> \mathrm{(A) \ } 15\qquad \mathrm{(B) \ } 18\qquad \mathrm{(C) \ } 20\qquad \mathrm{(D) \ } 24\ label("$y$",(15,-4),N);
  15 KB (2,223 words) - 13:43, 28 December 2020
• 2005 AMC 12A Problems
  == Problem 15 == [[2005 AMC 12A Problems/Problem 15|Solution]]
  13 KB (1,971 words) - 13:03, 19 February 2020
• 2004 AMC 12A Problems
  ...Players <math>A</math>, <math>B</math> and <math>C</math> start with <math>15</math>, <math>14</math> and <math>13</math> tokens, respectively. How many == Problem 15 ==
  13 KB (1,953 words) - 00:31, 26 January 2023
• 2003 AMC 12A Problems
  A solid box is <math>15</math> cm by <math>10</math> cm by <math>8</math> cm. A new solid is formed == Problem 15 ==
  13 KB (1,955 words) - 21:06, 19 August 2023
• 2002 AMC 12A Problems
  <math> \mathrm{(A) \ } 15\qquad \mathrm{(B) \ } 34\qquad \mathrm{(C) \ } 43\qquad \mathrm{(D) \ } 51\ ...xt{(A)}\ 12 \qquad \text{(B)}\ 13 \qquad \text{(C)}\ 14 \qquad \text{(D)}\ 15 \qquad \text{(E)} 16</math>
  12 KB (1,792 words) - 13:06, 19 February 2020

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