2020 AIME I Problems/Problem 7

Revision as of 16:15, 12 March 2020 by Awang11 (talk | contribs) (Solution)

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Problem

Solution

We will be selecting girls, but not selecting boys. We claim that the amount of girls selected and the amount of guys not selected adds to $12$. This is easy to see: if $k$ women were chosen, then $k + (11 - k + 1) = 12$. Therefore, we simply take $\binom{23}{12} \implies \boxed{081}$. ~awang11's sol

See Also

2020 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions

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