1995 AJHSME Problems/Problem 6
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Problem
Figures ,
, and
are squares. The perimeter of
is
and the perimeter of
is
. The perimeter of
is
Solution
Since the perimeter of
, each side is
.
Since the perimeter of is
, each side is
.
The side of is equal to the sum of the sides of
and
. Therefore, the side of
is
.
Since is also a square, it has an perimeter of
, and the answer is
.
See Also
1995 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |