2012 AMC 8 Problems/Problem 13
Problem
Jamar bought some pencils costing more than a penny each at the school bookstore and paid . Sharona bought some of the same pencils and paid
. How many more pencils did Sharona buy than Jamar?
Solution
We assume that the price of the pencils remains constant. Convert and
to cents. Since the price of the pencils is more than one penny, we can find the price of one pencil (in cents) by taking the greatest common divisor of
and
, which is
. Therefore, Jamar bought
pencils and Sharona bought
pencils. Thus, Sharona bought
more pencils than Jamar.
See Also
2012 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
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