1974 AHSME Problems/Problem 5
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Problem
Given a quadrilateral inscribed in a circle with side extended beyond to point , if and , find .
Solution
Since is cyclic, opposite angles must sum to . Therefore, , and . Notice also that and form a linear pair, and so they sum to . Therefore, . Notice that the answer didn't even depend on .
See Also
1974 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
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