1952 AHSME Problems/Problem 19
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Problem
Angle of triangle is trisected by and which meet at and respectively. Then:
Solution
Using the Angle Bisector Theorem on and , we find that and . Rewriting this to better fit our answer choices gives and . Hence, .
See also
1952 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
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