1952 AHSME Problems/Problem 24
Revision as of 00:06, 25 January 2014 by Throwaway1489 (talk | contribs)
Problem
In the figure, it is given that angle , , , , and . The area of quadrilateral is:
Solution
Note that, as right triangles sharing , .
Because the sides of are in the ratio , .
The sides of our triangles are in the ratio , and the ratio of their areas is .
, and .
See also
1952 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.