1983 AHSME Problems/Problem 3
Revision as of 06:19, 18 May 2016 by Quantummech (talk | contribs) (Created page with "==Problem 3== Three primes <math>p,q</math>, and <math>r</math> satisfy <math>p+q = r</math> and <math>1 < p < q</math>. Then <math>p</math> equals <math>\textbf{(A)}\ 2\qqu...")
Problem 3
Three primes , and satisfy and . Then equals
Solution
We are given that and are primes. In order to sum two another prime, either or has to be even, because the sum of an odd and an even is odd. The only odd prime is , and it is also the smallest prime, so therefore, the answer is
See Also
1983 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.