Difference between revisions of "1952 AHSME Problems/Problem 33"
(Created page with "== Problem == A circle and a square have the same perimeter. Then: <math>\text{(A) their areas are equal}\qquad</math> <math>\text{(B) the area of the circle is the greater} ...") |
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A circle and a square have the same perimeter. Then: | A circle and a square have the same perimeter. Then: | ||
| − | <math>\text{(A) their areas are equal}\qquad | + | <math>\text{(A) their areas are equal}\qquad\\ |
| − | + | \text{(B) the area of the circle is the greater} \qquad\\ | |
| − | + | \text{(C) the area of the square is the greater} \qquad\\ | |
| − | + | \text{(D) the area of the circle is } \pi \text{ times the area of the square}\qquad\\ | |
| − | + | \text{(E) none of these}</math> | |
== Solution == | == Solution == | ||
Revision as of 21:49, 2 October 2014
Problem
A circle and a square have the same perimeter. Then:
Solution
See also
| 1952 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 32 |
Followed by Problem 34 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
