Difference between revisions of "1958 AHSME Problems/Problem 40"
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== Problem == | == Problem == | ||
− | Given <math> a_0 | + | Given <math> a_0 = 1</math>, <math> a_1 = 3</math>, and the general relation <math> a_n^2 - a_{n - 1}a_{n + 1} = (-1)^n</math> for <math> n \ge 1</math>. Then <math> a_3</math> equals: |
<math> \textbf{(A)}\ \frac{13}{27}\qquad | <math> \textbf{(A)}\ \frac{13}{27}\qquad | ||
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\textbf{(C)}\ 21\qquad | \textbf{(C)}\ 21\qquad | ||
\textbf{(D)}\ 10\qquad | \textbf{(D)}\ 10\qquad | ||
− | \textbf{(E)}\ | + | \textbf{(E)}\ -17</math> |
== Solution == | == Solution == |
Revision as of 23:25, 13 March 2015
Problem
Given , , and the general relation for . Then equals:
Solution
See Also
1958 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 39 |
Followed by Problem 41 | |
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All AHSME Problems and Solutions |
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