Difference between revisions of "1964 AHSME Problems/Problem 32"

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<math> \textbf{(E) }a(b+c+d)=c(a+b+d)</math>
 
<math> \textbf{(E) }a(b+c+d)=c(a+b+d)</math>
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==See Also==
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{{AHSME 40p box|year=1964|num-b=31|num-a=33}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Revision as of 22:16, 24 July 2019

Problem

If $\dfrac{a+b}{b+c}=\dfrac{c+d}{d+a}$, then:

$\textbf{(A) }a \text{ must equal }c\qquad\textbf{(B) }a+b+c+d\text{ must equal zero}\qquad$

$\textbf{(C) }\text{either }a=c\text{ or }a+b+c+d=0\text{, or both}\qquad$

$\textbf{(D) }a+b+c+d\ne 0\text{ if }a=c\qquad$

$\textbf{(E) }a(b+c+d)=c(a+b+d)$

See Also

1964 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 31
Followed by
Problem 33
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All AHSME Problems and Solutions

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