1992 AJHSME Problems/Problem 9

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Problem 9

The population of a small town is $480$. The graph indicates the number of females and males in the town, but the vertical scale-values are omitted. How many males live in the town?

[asy] draw((0,13)--(0,0)--(20,0));  draw((3,0)--(3,10)--(8,10)--(8,0)); draw((3,5)--(8,5)); draw((11,0)--(11,5)--(16,5)--(16,0));  label("$\textbf{POPULATION}$",(10,11),N); label("$\textbf{F}$",(5.5,0),S);  label("$\textbf{M}$",(13.5,0),S); [/asy]

$\text{(A)}\ 120 \qquad \text{(B)}\ 160 \qquad \text{(C)}\ 200 \qquad \text{(D)}\ 240 \qquad \text{(E)}\ 360$

Solution

The graph show that the ratio of men to total population is $\frac{1}{3}$, so the total number of men is $\frac{1}{3} \times 480= \boxed{\text{(B)}\ 160}$.

Solution 2

The graph shows $3$ equal squares, each with value $x$. So $3x = 480$, so $x = \boxed{160}$.

See Also

1992 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
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All AJHSME/AMC 8 Problems and Solutions

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