Difference between revisions of "1993 AJHSME Problems/Problem 1"
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==Solution 2== | ==Solution 2== | ||
− | We know that if we want a product of 36, both numbers have to be positive or negative. Scanning the number pairs, the only choice with one negative number and one positive number is <math>\boxed{\text{(C)}}</math> | + | We know that if we want a product of 36, both numbers have to be positive or negative. Scanning the number pairs, the only choice with one negative number and one positive number is <math>\boxed{\text{(C)}}</math> |
+ | ~fn106068 | ||
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==See Also== | ==See Also== | ||
{{AJHSME box|year=1993|before=First<br />Question|num-a=2}} | {{AJHSME box|year=1993|before=First<br />Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 19:55, 23 July 2021
Contents
Problem
Which pair of numbers does NOT have a product equal to ?
Solution 1
A. The ordered pair has a product of
B. The ordered pair has a product of
C. The ordered pair has a product of
D. The ordered pair has a product of
E. The ordered pair has a product of
Since C is the only ordered pair which doesn't equal 36, is the answer.
Solution 2
We know that if we want a product of 36, both numbers have to be positive or negative. Scanning the number pairs, the only choice with one negative number and one positive number is ~fn106068
See Also
1993 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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