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Difference between revisions of "2002 AMC 12A Problems"

(added problem 1)
(Problem 1)
Line 4: Line 4:
 
<math>\displaystyle (2x+3)(x-4)+(2x+3)(x-6)=0 </math>
 
<math>\displaystyle (2x+3)(x-4)+(2x+3)(x-6)=0 </math>
  
<math> \mathrm{(A) \ } \frac{7}{2}\qquad \mathrm{(B) \ } 4\qquad \mathrm{(C) \ } 5\qquad \mathrm{(D) \ } 7</math>
+
<math> \mathrm{(A) \ } \frac{7}{2}\qquad \mathrm{(B) \ } 4\qquad \mathrm{(C) \ } 5\qquad \mathrm{(D) \ } 7\qquad \mathrm{(E) \ } 13 </math>
 
 
<math>\mathrm{(E) \ } 13 </math>
 
  
 
[[2002 AMC 12A Problems/Problem 1|Solution]]
 
[[2002 AMC 12A Problems/Problem 1|Solution]]

Revision as of 02:04, 4 February 2007