Difference between revisions of "2009 AMC 12A Problems/Problem 2"
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This is choice <math>\boxed{\text{C}}</math>. | This is choice <math>\boxed{\text{C}}</math>. | ||
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+ | Interesting sidenote: The continued fraction <math>1 + \frac {1}{1 + \frac {1}{1 + 1....}}</math> is equal to the golden ratio, or <math>\frac{1+\sqrt{5}}{2}</math>. | ||
== See Also == | == See Also == |
Latest revision as of 09:19, 8 June 2021
- The following problem is from both the 2009 AMC 12A #2 and 2009 AMC 10A #3, so both problems redirect to this page.
Problem
Which of the following is equal to ?
Solution
We compute:
This is choice .
Interesting sidenote: The continued fraction is equal to the golden ratio, or .
See Also
2009 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2009 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.