Difference between revisions of "2012 AMC 8 Problems/Problem 2"

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==Problem==
 
In the country of East Westmore, statisticians estimate there is a baby born every <math> 8 </math> hours and a death every day. To the nearest hundred, how many people are added to the population of East Westmore each year?
 
In the country of East Westmore, statisticians estimate there is a baby born every <math> 8 </math> hours and a death every day. To the nearest hundred, how many people are added to the population of East Westmore each year?
  
 
<math> \textbf{(A)}\hspace{.05in}600\qquad\textbf{(B)}\hspace{.05in}700\qquad\textbf{(C)}\hspace{.05in}800\qquad\textbf{(D)}\hspace{.05in}900\qquad\textbf{(E)}\hspace{.05in}1000 </math>
 
<math> \textbf{(A)}\hspace{.05in}600\qquad\textbf{(B)}\hspace{.05in}700\qquad\textbf{(C)}\hspace{.05in}800\qquad\textbf{(D)}\hspace{.05in}900\qquad\textbf{(E)}\hspace{.05in}1000 </math>
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==Solution==
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There are <math>24\text{ hours}\div8\text{ hours} = 3</math> births and one death everyday in East Westmore. Therefore, the population increases by <math>3</math> - <math>1</math> = <math>2</math> people everyday. Thus, there are <math>2 \times 365 = 730</math> people added to the population every year. Rounding, we find the answer is <math>\boxed{\textbf{(B)}\ 700}</math>.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2012|num-b=1|num-a=3}}
 
{{AMC8 box|year=2012|num-b=1|num-a=3}}
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{{MAA Notice}}

Latest revision as of 20:44, 14 August 2017

Problem

In the country of East Westmore, statisticians estimate there is a baby born every $8$ hours and a death every day. To the nearest hundred, how many people are added to the population of East Westmore each year?

$\textbf{(A)}\hspace{.05in}600\qquad\textbf{(B)}\hspace{.05in}700\qquad\textbf{(C)}\hspace{.05in}800\qquad\textbf{(D)}\hspace{.05in}900\qquad\textbf{(E)}\hspace{.05in}1000$

Solution

There are $24\text{ hours}\div8\text{ hours} = 3$ births and one death everyday in East Westmore. Therefore, the population increases by $3$ - $1$ = $2$ people everyday. Thus, there are $2 \times 365 = 730$ people added to the population every year. Rounding, we find the answer is $\boxed{\textbf{(B)}\ 700}$.

See Also

2012 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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