Difference between revisions of "2017 AMC 8 Problems/Problem 3"

(6 intermediate revisions by 5 users not shown)
Line 1: Line 1:
==Problem 3==
+
==Problem==
  
 
What is the value of the expression <math>\sqrt{16\sqrt{8\sqrt{4}}}</math>?
 
What is the value of the expression <math>\sqrt{16\sqrt{8\sqrt{4}}}</math>?
Line 7: Line 7:
 
==Solution==
 
==Solution==
  
To solve the equation<math>\sqrt{16\sqrt{8\sqrt{4}}}</math>. The square root of four is <math>2</math>. Multiply this by <math>8</math> to get <math>16</math>, and the square root of sixteen is <math>4</math>, and multiply this by <math>16</math> to get <math>64</math>. The square root of <math>64</math> is <math>8</math>, hence the answer (C).
+
<math>\sqrt{16\sqrt{8\sqrt{4}}}</math> = <math>\sqrt{16\sqrt{8\cdot 2}}</math> = <math>\sqrt{16\sqrt{16}}</math> = <math>\sqrt{16\cdot 4}</math> = <math>\sqrt{64}</math> = <math>\boxed{\textbf{(C)}\ 8}</math>.
 
+
==Video Solution==
~pegasuswa
+
https://youtu.be/cY4NYSAD0vQ
  
 
==See Also==
 
==See Also==

Revision as of 13:58, 18 January 2021

Problem

What is the value of the expression $\sqrt{16\sqrt{8\sqrt{4}}}$?

$\textbf{(A) }4\qquad\textbf{(B) }4\sqrt{2}\qquad\textbf{(C) }8\qquad\textbf{(D) }8\sqrt{2}\qquad\textbf{(E) }16$

Solution

$\sqrt{16\sqrt{8\sqrt{4}}}$ = $\sqrt{16\sqrt{8\cdot 2}}$ = $\sqrt{16\sqrt{16}}$ = $\sqrt{16\cdot 4}$ = $\sqrt{64}$ = $\boxed{\textbf{(C)}\ 8}$.

Video Solution

https://youtu.be/cY4NYSAD0vQ

See Also

2017 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png