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first shout of 2026
by
Yiyj1, Apr 11, 2025, 2:10 AM
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first shout in 2025
by
Captainscrubz, Jan 28, 2025, 5:32 PM
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289322 is crazy
by
Tem8, Nov 20, 2024, 3:13 AM
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orz evan :orz: thx for diamond
by
Likeminded2017, Nov 17, 2024, 5:44 AM
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a relic of the past
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Clew28, Jul 25, 2024, 8:55 PM
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why'd you look at this? You leave me no choice...
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aidending, Jul 14, 2024, 11:49 PM
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hi evan thanks for the diamond
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Scilyse, Feb 8, 2024, 10:16 PM
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woa hi evan
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crazyeyemoody907, Aug 20, 2023, 9:14 PM
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just google "nontrivial progress" for this blog!
by
gracemoon124, Jul 29, 2023, 10:40 PM
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HI GUYS!
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unknown12, Apr 16, 2023, 3:04 AM
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isn't the shoutbox a bit too big?
by
cinnamon_e, Apr 1, 2023, 7:56 PM
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Omg market moment
by
GrantStar, Mar 19, 2023, 12:50 AM
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no
by
v4913, Mar 18, 2023, 9:56 PM
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do shouts bring this up the blogroll?
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vsamc, Mar 4, 2023, 4:46 PM
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hi!
first shout of 2023 
by
purplepenguin2, Feb 13, 2023, 7:21 AM
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Contrib please?
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jjfun1, Jun 19, 2010, 3:57 PM
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Alright, completed
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v_Enhance, Jun 18, 2010, 11:49 PM
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Can I contrib?
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HappyFace241, Jun 16, 2010, 3:34 AM
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What scrollbar?
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dragon96, Jun 13, 2010, 8:59 PM
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Okay, done
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v_Enhance, Jun 13, 2010, 3:18 PM
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Can I be a contributor???
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blabla4198, Jun 13, 2010, 5:54 AM
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LOL.
HAI EVAN. YOUR BLOG IS FUNNY.
I LIKE YOUR INCREDIBLY HIGH STANDARDS FOR EVERYTHING.
by
Anonymous, Apr 19, 2010, 3:57 AM
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Yes I did make AIME
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EggyLv.999, Apr 7, 2010, 12:24 AM
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Meh. I didn't even make AIME -.-
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Anonymous, Mar 29, 2010, 7:25 AM
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Meh. I didn't even make AIME -.-
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ilovepi, Mar 29, 2010, 12:17 AM
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Heh, everyone seems to be making stupid mistakes... so why is it they still scored higher than me?
Haha, I have made everyone in this shoutbox a contributor 
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v_Enhance, Mar 19, 2010, 2:43 AM
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Should have...should have...should have...
Define it.
I "should have" got a 15. But I misbubbled a lot.
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AIME15, Mar 18, 2010, 12:37 AM
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I got a 6 too. and an index of 190.5
I should've gotten a 10.... but no one likes me.
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SonyWii, Mar 18, 2010, 12:06 AM
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Trivial Progress
by
dragon96, Mar 14, 2010, 5:55 AM
by v_Enhance, Aug 4, 2012, 7:34 PM 
be an (possibly infinite) multiset of positive integers greater than one such that the multiplicity of each element is finite, and for each 
, there are finitely many elements of 
. Define 
![\[ f(n) = \sum_{\substack{a \in A \\ 1 \le k \le a}} \left[ e^{\frac{2\pi ik}{a}} \right]^n. \]](//latex.artofproblemsolving.com/3/4/e/34e24b6295cea5e53c95d99d1e0d7f896eae1fa6.png)
Is it possible that 
can be expressed as a nonconstant polynomial with complex coefficients?
be an (possibly infinite) multiset of positive integers greater than one such that the multiplicity of each element is finite, and for each 
, there are finitely many elements of 
. Define 
![\[ f(n) = \sum_{\substack{a \in A \\ 1 \le k \le a}} \left[ e^{\frac{2\pi ik}{a}} \right]^n. \]](http://latex.artofproblemsolving.com/3/4/e/34e24b6295cea5e53c95d99d1e0d7f896eae1fa6.png)
Is it possible that 
can be expressed as a nonconstant polynomial with complex coefficients?
in 
,
April 2023
February 2023