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k a July Highlights and 2025 AoPS Online Class Information
jwelsh   0
Jul 1, 2025
We are halfway through summer, so be sure to carve out some time to keep your skills sharp and explore challenging topics at AoPS Online and our AoPS Academies (including the Virtual Campus)!

[list][*]Over 60 summer classes are starting at the Virtual Campus on July 7th - check out the math and language arts options for middle through high school levels.
[*]At AoPS Online, we have accelerated sections where you can complete a course in half the time by meeting twice/week instead of once/week, starting on July 8th:
[list][*]MATHCOUNTS/AMC 8 Basics
[*]MATHCOUNTS/AMC 8 Advanced
[*]AMC Problem Series[/list]
[*]Plus, AoPS Online has a special seminar July 14 - 17 that is outside the standard fare: Paradoxes and Infinity
[*]We are expanding our in-person AoPS Academy locations - are you looking for a strong community of problem solvers, exemplary instruction, and math and language arts options? Look to see if we have a location near you and enroll in summer camps or academic year classes today! New locations include campuses in California, Georgia, New York, Illinois, and Oregon and more coming soon![/list]

MOP (Math Olympiad Summer Program) just ended and the IMO (International Mathematical Olympiad) is right around the corner! This year’s IMO will be held in Australia, July 10th - 20th. Congratulations to all the MOP students for reaching this incredible level and best of luck to all selected to represent their countries at this year’s IMO! Did you know that, in the last 10 years, 59 USA International Math Olympiad team members have medaled and have taken over 360 AoPS Online courses. Take advantage of our Worldwide Online Olympiad Training (WOOT) courses
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Are you tired of the heat and thinking about Fall? You can plan your Fall schedule now with classes at either AoPS Online, AoPS Academy Virtual Campus, or one of our AoPS Academies around the US.

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0 replies
jwelsh
Jul 1, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
Foil
Silverfalcon   33
N 9 minutes ago by superhuman233
$(1+x^2)(1-x^3)$ equals

$ \text{(A)}\ 1 - x^5\qquad\text{(B)}\ 1 - x^6\qquad\text{(C)}\ 1+ x^2 -x^3\qquad \\ \text{(D)}\ 1+x^2-x^3-x^5\qquad \text{(E)}\ 1+x^2-x^3-x^6 $
33 replies
Silverfalcon
Oct 21, 2005
superhuman233
9 minutes ago
Cutting square into three congruent rectangles
Silverfalcon   14
N 14 minutes ago by henryli3333
A square is cut into three rectangles along two lines parallel to a side, as shown. If the perimeter of each of the three rectangles is 24, then the area of the original square is

IMAGE

$\text{(A)} \ 24 \qquad \text{(B)} \ 36 \qquad \text{(C)} \ 64 \qquad \text{(D)} \ 81 \qquad \text{(E)} \ 96$
14 replies
Silverfalcon
Dec 9, 2005
henryli3333
14 minutes ago
The 24 Game, but with a twist!
PikaPika999   327
N 25 minutes ago by henryli3333
So many people know the 24 game, where you try to create the number 24 from using other numbers, but here's a twist:

You can only use the number 24 (up to 5 times) to try to make other numbers :)

the limit is 5 times because then people could just do $\frac{24}{24}+\frac{24}{24}+\frac{24}{24}+...$ and so on to create any number!

honestly, I feel like with only addition, subtraction, multiplication, and division, you can't get pretty far with this, so you can use any mathematical operations!

Banned functions
327 replies
PikaPika999
Jul 1, 2025
henryli3333
25 minutes ago
9 Worst math subject
a.zvezda   0
27 minutes ago
Mine is geo and C&P because it's really annoying and last year, I got 16 on the AMC 8 when I sillied a few geo and C&P problems. :wallbash_red:
0 replies
a.zvezda
27 minutes ago
0 replies
diophantine with factorials and exponents
skellyrah   17
N an hour ago by SimplisticFormulas
find all positive integers $a,b,c$ such that $$ a! + 5^b = c^3 $$
17 replies
skellyrah
May 30, 2025
SimplisticFormulas
an hour ago
Locus of XZ \cap ZT
NO_SQUARES   3
N an hour ago by Kappa_Beta_725
Source: 9.7 of XX Geometrical Olympiad in honour of I.F.Sharygin
Let $P$ and $Q$ be arbitrary points on the side $BC$ of triangle ABC such that $BP = CQ$. The common points of segments $AP$ and $AQ$ with the incircle form a quadrilateral $XYZT$. Find the locus of common points of diagonals of such quadrilaterals.
3 replies
NO_SQUARES
Aug 6, 2024
Kappa_Beta_725
an hour ago
An interesting combination problem
Math291   7
N an hour ago by bluedino24
Given a unit square grid of size 4×6 as shown in the figure below, an ant crawls from point A. Each time it moves, it crawls along the side of a unit square to an adjacent grid point.
IMAGE
How many number of ways to complete a path so that after exactly 12 moves, it stops at position B?
7 replies
Math291
Today at 12:02 PM
bluedino24
an hour ago
Existence of numbers
Timta27   0
an hour ago
Source: own
Is it possible to find four natural numbers $a_{1},a_{2},a_{3},a_{4}$ ($1 \leq a_{1}<a_{2}<a_{3}<a_{4}$) such that for all $i \neq j$ ($1 \leq i,j \leq 4$): $\frac{a_{i}^{2}+a_{j}^2}{a_{i}-a_{j}} \in \mathbb{Z}$
and there are exactly three odd numbers among $a_{1},a_{2},a_{3},a_{4}$?
0 replies
Timta27
an hour ago
0 replies
f(x + y) + f(x − y) = 2f(x) + 2f(y) in Q
parmenides51   5
N 2 hours ago by Fly_into_the_sky
Source: Nordic Mathematical Contest 1998 #1
Determine all functions $ f$ defined in the set of rational numbers and taking their values in the same set such that the equation $ f(x + y) + f(x - y) = 2f(x) + 2f(y)$ holds for all rational numbers $x$ and $y$.
5 replies
parmenides51
Oct 3, 2017
Fly_into_the_sky
2 hours ago
Doing Operations on a Table
EthanWYX2009   1
N 2 hours ago by YaoAOPS
Source: 2025 June 谜之竞赛-5, proposed by me :-D
Let \( m \geq 3 \) be an integer, and let \( \mathcal F \) denote the set of all permutations of \(\{1, 2, \cdots, m\}\).

Let \( n \) be a positive integer. Consider an \( n \times n \) grid, where initially each cell of the grid is filled with a permutation from \( \mathcal F \). An operation is defined as follows: select a permutation \( \tau \in \mathcal F \) and choose a row or column of the grid, then for each cell in the selected row (or column), replace the current permutation \( \sigma \) in the cell with \( \sigma \circ \tau \). Let \( f(n) \) be the smallest integer such that for any initial configuration of permutations in the grid, if it is possible to transform all permutations into the identity permutation through a finite number of operations, then this can be achieved in no more than \( f(n) \) operations.

Prove that there exist positive real numbers \( c_1 < c_2 \) such that for any integer \( n \geq 3 \), the following holds:
\[c_1 \cdot \frac{n^2}{\ln n} < f(n) < c_2 \cdot \frac{n^2}{\ln n} \]
1 reply
EthanWYX2009
Jun 29, 2025
YaoAOPS
2 hours ago
Inequality where a+b+c=3
leannan-capall   16
N 2 hours ago by mudkip42
Source: Irish Mathematical Olympiad 2023 Problem 8
Suppose that $a, b, c$ are positive real numbers and $a + b + c = 3$. Prove that

$$\frac{a+b}{c+2} + \frac{b+c}{a+2} + \frac{c+a}{b+2} \geq 2$$
and determine when equality holds.
16 replies
leannan-capall
May 14, 2023
mudkip42
2 hours ago
short geo problem
SYBARUPEMULA   1
N 2 hours ago by ricarlos
On a right-angled trapezoid $ABCD$, $\angle B = \angle C = 90^o$ and $BC = \sqrt{AB \times CD}$. Prove that
$$\tan \angle DAC = \tan^3 \angle DBC.$$
1 reply
1 viewing
SYBARUPEMULA
Yesterday at 10:17 AM
ricarlos
2 hours ago
IMO MOHS rating predictions
ohiorizzler1434   11
N 2 hours ago by IMO2027
Everybody, with the IMO about to happen soon, what are your predictions for the MOHS ratings of the problems? I predict 10 20 40 15 25 45.
11 replies
ohiorizzler1434
Today at 4:48 AM
IMO2027
2 hours ago
Ratios of LCM and GCD
Brut3Forc3   19
N 3 hours ago by IMO2027
Source: 1972 USAMO Problem 1
The symbols $ (a,b,\ldots,g)$ and $ [a,b,\ldots,g]$ denote the greatest common divisor and least common multiple, respectively, of the positive integers $ a,b,\ldots,g$. For example, $ (3,6,18)=3$ and $ [6,15]=30$. Prove that \[ \frac{[a,b,c]^2}{[a,b][b,c][c,a]}=\frac{(a,b,c)^2}{(a,b)(b,c)(c,a)}.\]
19 replies
Brut3Forc3
Mar 6, 2010
IMO2027
3 hours ago
Interesting Combinatorics Problem
Ro.Is.Te.   14
N May 29, 2025 by Wolfpierce
Amanda has $1000$ red marbles, $2000$ yellow marbles, $3000$ green marbles, and $4000$ blue marbles. If Amanda takes the marbles one by one without replacing them until the $3999th$ marble. Then the probability that the $4000th$ marble is red is?
14 replies
Ro.Is.Te.
May 23, 2025
Wolfpierce
May 29, 2025
Interesting Combinatorics Problem
G H J
G H BBookmark kLocked kLocked NReply
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Ro.Is.Te.
21 posts
#1
Y by
Amanda has $1000$ red marbles, $2000$ yellow marbles, $3000$ green marbles, and $4000$ blue marbles. If Amanda takes the marbles one by one without replacing them until the $3999th$ marble. Then the probability that the $4000th$ marble is red is?
This post has been edited 2 times. Last edited by Ro.Is.Te., May 23, 2025, 11:51 AM
Reason: LaTeX
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CJB19
178 posts
#2 • 4 Y
Y by Demetri, sbarrack, Pengu14, aidan0626
?
This post has been edited 1 time. Last edited by CJB19, May 23, 2025, 1:01 PM
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sultanine
902 posts
#3
Y by
CJB19 wrote:
?

yeah I kinda agree with u
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SpeedCuber7
1895 posts
#5
Y by
CJB19 wrote:
?

nope

there are 10000 marbles in the bin, not 4000
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CJB19
178 posts
#6
Y by
Oh wait I'm silly
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aidan0626
2069 posts
#7 • 2 Y
Y by Pengu14, BAM10
i'm pretty sure the answer is still correct tho lol
the chance of getting a red marble is the same regardless of how many you've already taken out
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SpeedCuber7
1895 posts
#8
Y by
aidan0626 wrote:
i'm pretty sure the answer is still correct tho lol
the chance of getting a red marble is the same regardless of how many you've already taken out

no it isn't??

if you take out 3999 blues, then the probability is 1000/6001
Z K Y
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aidan0626
2069 posts
#9
Y by
aidan0626 wrote:
i'm pretty sure the answer is still correct tho lol
the chance of getting a red marble is the same regardless of how many you've already taken out

no it isn't??

if you take out 3999 blues, then the probability is 1000/6001

do you understand how probability works
where in the problem did it say 3999 blues are taken out
well i don't want to actually write the whole thing up noooo :(
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SpeedCuber7
1895 posts
#10
Y by
aidan0626 wrote:
aidan0626 wrote:
i'm pretty sure the answer is still correct tho lol
the chance of getting a red marble is the same regardless of how many you've already taken out

no it isn't??

if you take out 3999 blues, then the probability is 1000/6001

do you understand how probability works
where in the problem did it say 3999 blues are taken out
well i don't want to actually write the whole thing up noooo :(

what if they take a red out in one of the 3999 marbles? then the probability must be different
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Aaronjudgeisgoat
935 posts
#11
Y by
im pretty sure post 2 is right.

it doesnt matter what the first 3999 numbers are, just initially choose what the 4000th marble is and nothing else matters.
for example, consider this. what if instead the problem was as follows: Amanda has $1000$ red marbles, $2000$ yellow marbles, $3000$ green marbles, and $4000$ blue marbles. IAmanda takes the marbles one by one, from the last marble to the $6002th$ marble. Then the probability that the $1st$ marble is red is?

same problem, ur removing 3999 marbles, and u wanna find the probability that the first one is red. you can see how this is the same as the previosu problem right? and the answer is still 1/10

ur argument is that it depends on what the 3999 marbles are. and of course, thats true. but in the end, it all averages out because both solutions are the same, except ur looking at the problem in a different way
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ZMB038
444 posts
#12
Y by
I think it’s just $\frac{1}{10}$
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LXC007
176 posts
#13
Y by
sol
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RedChameleon
1257 posts
#14
Y by
The confusion this is giving me is the same confusion I get when contemplating the monty hall problem
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Juran2014
1 post
#15
Y by
.............
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Wolfpierce
37 posts
#16
Y by
Yeah just 1/10 I think I don't know I'm not even in 5th grade
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