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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Today at 3:18 PM
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
[*]April 8th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS State Discussion
April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers[/list]
Our full course list for upcoming classes is below:
All classes run 7:30pm-8:45pm ET/4:30pm - 5:45pm PT unless otherwise noted.

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0 replies
jlacosta
Today at 3:18 PM
0 replies
k a My Retirement & New Leadership at AoPS
rrusczyk   1571
N Mar 26, 2025 by SmartGroot
I write today to announce my retirement as CEO from Art of Problem Solving. When I founded AoPS 22 years ago, I never imagined that we would reach so many students and families, or that we would find so many channels through which we discover, inspire, and train the great problem solvers of the next generation. I am very proud of all we have accomplished and I’m thankful for the many supporters who provided inspiration and encouragement along the way. I'm particularly grateful to all of the wonderful members of the AoPS Community!

I’m delighted to introduce our new leaders - Ben Kornell and Andrew Sutherland. Ben has extensive experience in education and edtech prior to joining AoPS as my successor as CEO, including starting like I did as a classroom teacher. He has a deep understanding of the value of our work because he’s an AoPS parent! Meanwhile, Andrew and I have common roots as founders of education companies; he launched Quizlet at age 15! His journey from founder to MIT to technology and product leader as our Chief Product Officer traces a pathway many of our students will follow in the years to come.

Thank you again for your support for Art of Problem Solving and we look forward to working with millions more wonderful problem solvers in the years to come.

And special thanks to all of the amazing AoPS team members who have helped build AoPS. We’ve come a long way from here:IMAGE
1571 replies
rrusczyk
Mar 24, 2025
SmartGroot
Mar 26, 2025
calculate the perimeter of triangle MNP
PennyLane_31   1
N 19 minutes ago by TheBaiano
Source: 2024 5th OMpD L2 P2 - Brazil - Olimpíada Matemáticos por Diversão
Let $ABCD$ be a convex quadrilateral, and $M$, $N$, and $P$ be the midpoints of diagonals $AC$ and $BD$, and side $AD$, respectively. Also, suppose that $\angle{ABC} + \angle{DCB} = 90$ and that $AB = 6$, $CD = 8$. Calculate the perimeter of triangle $MNP$.
1 reply
PennyLane_31
Oct 16, 2024
TheBaiano
19 minutes ago
egmo 2018 p4
microsoft_office_word   28
N 38 minutes ago by akliu
Source: EGMO 2018 P4
A domino is a $ 1 \times 2 $ or $ 2 \times 1 $ tile.
Let $n \ge 3 $ be an integer. Dominoes are placed on an $n \times n$ board in such a way that each domino covers exactly two cells of the board, and dominoes do not overlap. The value of a row or column is the number of dominoes that cover at least one cell of this row or column. The configuration is called balanced if there exists some $k \ge 1 $ such that each row and each column has a value of $k$. Prove that a balanced configuration exists for every $n \ge 3 $, and find the minimum number of dominoes needed in such a configuration.
28 replies
microsoft_office_word
Apr 12, 2018
akliu
38 minutes ago
Polynomial
EtacticToe   3
N 43 minutes ago by EmersonSoriano
Source: Own
Let $f(x)$ be a monic polynomial with integer coefficient. And suppose there exist 4 distinct integer $a,b,c,d$ such that $f(a)=…=f(d)=5$.

Find all $k$ such that $f(k)=8$
3 replies
EtacticToe
Dec 14, 2024
EmersonSoriano
43 minutes ago
inequalities hard
Cobedangiu   5
N an hour ago by Primeniyazidayi
problem
5 replies
Cobedangiu
Mar 31, 2025
Primeniyazidayi
an hour ago
No more topics!
Polynomials and their shift with all real roots and in common
Assassino9931   4
N Yesterday at 10:42 PM by Assassino9931
Source: Bulgaria Spring Mathematical Competition 2025 11.4
We call two non-constant polynomials friendly if each of them has only real roots, and every root of one polynomial is also a root of the other. For two friendly polynomials \( P(x), Q(x) \) and a constant \( C \in \mathbb{R}, C \neq 0 \), it is given that \( P(x) + C \) and \( Q(x) + C \) are also friendly polynomials. Prove that \( P(x) \equiv Q(x) \).
4 replies
Assassino9931
Mar 30, 2025
Assassino9931
Yesterday at 10:42 PM
Polynomials and their shift with all real roots and in common
G H J
G H BBookmark kLocked kLocked NReply
Source: Bulgaria Spring Mathematical Competition 2025 11.4
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Assassino9931
1219 posts
#1
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We call two non-constant polynomials friendly if each of them has only real roots, and every root of one polynomial is also a root of the other. For two friendly polynomials \( P(x), Q(x) \) and a constant \( C \in \mathbb{R}, C \neq 0 \), it is given that \( P(x) + C \) and \( Q(x) + C \) are also friendly polynomials. Prove that \( P(x) \equiv Q(x) \).
This post has been edited 1 time. Last edited by Assassino9931, Mar 30, 2025, 1:13 PM
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joeym2011
469 posts
#2
Y by
For the sake of contradiction, suppose $P$ and $Q$ are distinct, and without loss of generality, let $P$ have degree d higher than $Q$. Every root of $P(x)$ and $P(x)+C$ is a root of $(P-Q)(x)$, and $P(x)$ and $P(x)+C$ cannot share any roots. If $P$ has a root $r$ with multiplicity $m$, then $r$ has multiplicity $m-1$ in $P'$. Therefore, the number of distinct roots of $P$ equals $d$ minus the number of roots of $P'(x)=0$ where $P(x)=0$. Then the number of distinct roots of $(P-Q)(x)$ equals $2d$ minus the roots of $P'(x)$ with $P(x)=0$ or $P(x)+C=0$. The value is at least $2d-(d-1)>d$, creating a contradiction.
This post has been edited 1 time. Last edited by joeym2011, Mar 30, 2025, 2:33 PM
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AshAuktober
958 posts
#3
Y by
Am I missing something, or is this the infamous Putnam polynomial problem?
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Assassino9931
1219 posts
#4
Y by
I have seen this in a random book before indeed, but from which Putnam year is it?
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Assassino9931
1219 posts
#5
Y by
Found it now, it is Putnam 1956 B7
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