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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Yesterday at 3:18 PM
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
[*]April 8th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS State Discussion
April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Yesterday at 3:18 PM
0 replies
Complex numbers
RenheMiResembleRice   0
2 minutes ago
Solve the following attached.
0 replies
RenheMiResembleRice
2 minutes ago
0 replies
2 var inquality
sqing   1
N 5 minutes ago by lbh_qys
Source: Own
Let $ a,b> 0 $ and $ a+b= 2 . $ Prove that
$$ \frac{a^5}{a^5+ b^3}+ \frac{b^5}{b^5+ a^3}\leq 1$$$$ \frac{a^6}{a^5+ b^3}+ \frac{b^6}{b^5+ a^3}\leq 2$$
1 reply
2 viewing
sqing
15 minutes ago
lbh_qys
5 minutes ago
Harmonic Series and Infinite Sequences
steven_zhang123   2
N 8 minutes ago by NTstrucker
Source: China TST 2025 P19
Let $\left \{ x_n \right \} _{n\ge 1}$ and $\left \{ y_n \right \} _{n\ge 1}$ be two infinite sequences of integers. Prove that there exists an infinite sequence of integers $\left \{ z_n \right \} _{n\ge 1}$ such that for any positive integer \( n \), the following holds:

\[
\sum_{k|n} k \cdot z_k^{\frac{n}{k}} = \left( \sum_{k|n} k \cdot x_k^{\frac{n}{k}} \right) \cdot \left( \sum_{k|n} k \cdot y_k^{\frac{n}{k}} \right).
\]
2 replies
steven_zhang123
Mar 29, 2025
NTstrucker
8 minutes ago
Finding pairs of complex numbers with a certain property
Ciobi_   1
N 12 minutes ago by NTstrucker
Source: Romania NMO 2025 10.4
Find all pairs of complex numbers $(z,w) \in \mathbb{C}^2$ such that the relation \[|z^{2n}+z^nw^n+w^{2n} | = 2^{2n}+2^n+1 \]holds for all positive integers $n$.
1 reply
Ciobi_
Yesterday at 1:22 PM
NTstrucker
12 minutes ago
No more topics!
Prove that AY is tangent to (AEF)
geometry6   3
N Aug 18, 2024 by Amiralizakeri2007
Source: IMOC 2021 G8
Let $P$ be an arbitrary interior point of $\triangle ABC$, and $AP$, $BP$, $CP$ intersect $BC$, $CA$, $AB$ at $D$, $E$, $F$, respectively. Suppose that $M$ be the midpoint of $BC$, $\odot(AEF)$ and $\odot(ABC)$ intersect at $S$, $SD$ intersects $\odot(ABC)$ at $X$, and $XM$ intersects $\odot(ABC)$ at $Y$. Show that $AY$ is tangent to $\odot(AEF)$.
3 replies
geometry6
Aug 11, 2021
Amiralizakeri2007
Aug 18, 2024
Prove that AY is tangent to (AEF)
G H J
G H BBookmark kLocked kLocked NReply
Source: IMOC 2021 G8
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geometry6
304 posts
#1 • 1 Y
Y by tiendung2006
Let $P$ be an arbitrary interior point of $\triangle ABC$, and $AP$, $BP$, $CP$ intersect $BC$, $CA$, $AB$ at $D$, $E$, $F$, respectively. Suppose that $M$ be the midpoint of $BC$, $\odot(AEF)$ and $\odot(ABC)$ intersect at $S$, $SD$ intersects $\odot(ABC)$ at $X$, and $XM$ intersects $\odot(ABC)$ at $Y$. Show that $AY$ is tangent to $\odot(AEF)$.
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MP8148
888 posts
#2
Y by
We want to show that the spiral sim at $S$ sending $\overline{FE}$ to $\overline{BC}$ also sends $A$ to $Y$. By ratio lemma and spiral sim we have $$\frac{YB}{YC} = \frac{XC}{XB} = \frac{DC}{DB} \cdot \frac{SB}{SC} = \frac{DC}{DB} \cdot \frac{FB}{EC} = \frac{AF}{AE}$$where the last step follows by ceva. Since $\angle FAE = \angle BAC = \angle BYC$, we may conclude that $\triangle AFE \sim \triangle YBC$.
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hsiangshen
188 posts
#3
Y by
Let $EF \cap BC=G$. Notice that $S$ is the miquel point of complete quadrilateral $AB,BC,CA,EF$
Via some angle chasing we can easily conclude that the intersection of the line passing $A$ which is parallel to $EF$ and the line $GS$ lies on $\odot(ABC)$. Then by cross ratio:$$(B,C;D,G)=-1=(B,C;X,GS\cap\odot(ABC))=(B,C;M,Y(GS\cap\odot(ABC))\cap BC)$$$$\implies Y(GS\cap\odot(ABC))\parallel BC$$The rest of the problem can be finished by angle chasing. $\quad\blacksquare$
This post has been edited 5 times. Last edited by hsiangshen, Aug 26, 2021, 4:24 AM
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Amiralizakeri2007
45 posts
#4
Y by
Define $f(X)=\frac{XB}{XC}$.
$$f(Y)=\frac{1}{f(X)}=\frac{f(D)}{f(S)}=\frac{AE}{AF}$$Thus $\triangle YBC \sim \triangle AEF$ and we are done.
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