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IMO 2008, Question 2
delegat   63
N an hour ago by ezpotd
Source: IMO Shortlist 2008, A2
(a) Prove that
\[\frac {x^{2}}{\left(x - 1\right)^{2}} + \frac {y^{2}}{\left(y - 1\right)^{2}} + \frac {z^{2}}{\left(z - 1\right)^{2}} \geq 1\] for all real numbers $x$, $y$, $z$, each different from $1$, and satisfying $xyz=1$.

(b) Prove that equality holds above for infinitely many triples of rational numbers $x$, $y$, $z$, each different from $1$, and satisfying $xyz=1$.

Author: Walther Janous, Austria
63 replies
delegat
Jul 16, 2008
ezpotd
an hour ago
d(2025^{a_i}-1) divides a_{n+1}
navi_09220114   2
N 2 hours ago by mickeymouse7133
Source: TASIMO 2025 Day 2 Problem 5
Let $a_n$ be a strictly increasing sequence of positive integers such that for all positive integers $n\ge 1$
\[d(2025^{a_n}-1)|a_{n+1}.\]Show that for any positive real number $c$ there is a positive integers $N_c$ such that $a_n>n^c$ for all $n\geq N_c$.

Note. Here $d(m)$ denotes the number of positive divisors of the positive integer $m$.
2 replies
navi_09220114
Monday at 11:51 AM
mickeymouse7133
2 hours ago
Funky function
TheUltimate123   22
N 2 hours ago by jasperE3
Source: CJMO 2022/5 (https://aops.com/community/c594864h2791269p24548889)
Find all functions \(f:\mathbb R\to\mathbb R\) such that for all real numbers \(x\) and \(y\), \[f(f(xy)+y)=(x+1)f(y).\]
Proposed by novus677
22 replies
TheUltimate123
Mar 20, 2022
jasperE3
2 hours ago
R+ FE f(f(xy)+y)=(x+1)f(y)
jasperE3   0
2 hours ago
Source: p24734470
Find all functions $f:\mathbb R^+\to\mathbb R^+$ such that for all positive real numbers $x$ and $y$:
$$f(f(xy)+y)=(x+1)f(y).$$edit oops sorry I misinterpreted that the original poster had solved it, solvable tho
0 replies
jasperE3
2 hours ago
0 replies
Inequality with x+y+z=1.
FrancoGiosefAG   1
N 2 hours ago by Blackbeam999
Let $x,y,z$ be positive real numbers such that $x+y+z=1$. Show that
\[ \frac{x^2-yz}{x^2+x}+\frac{y^2-zx}{y^2+y}+\frac{z^2-xy}{z^2+z}\leq 0. \]
1 reply
FrancoGiosefAG
6 hours ago
Blackbeam999
2 hours ago
Find all numbers
Rushil   10
N 3 hours ago by SomeonecoolLovesMaths
Source: Indian RMO 1994 Problem 3
Find all 6-digit numbers $a_1a_2a_3a_4a_5a_6$ formed by using the digits $1,2,3,4,5,6$ once each such that the number $a_1a_2a_2\ldots a_k$ is divisible by $k$ for $1 \leq k \leq 6$.
10 replies
Rushil
Oct 25, 2005
SomeonecoolLovesMaths
3 hours ago
Some number theory
EeEeRUT   3
N 3 hours ago by MathLuis
Source: Thailand MO 2025 P9
Let $p$ be an odd prime and $S = \{1,2,3,\dots, p\}$
Assume that $U: S \rightarrow S$ is a bijection and $B$ is an integer such that $$B\cdot U(U(a)) - a \: \text{ is a multiple of} \: p \: \text{for all} \: a \in S$$Show that $B^{\frac{p-1}{2}} -1$ is a multiple of $p$.
3 replies
EeEeRUT
May 14, 2025
MathLuis
3 hours ago
Gcd
Rushil   5
N 3 hours ago by SomeonecoolLovesMaths
Source: Indian RMO 1994 problem 5
Let $A$ be a set of $16$ positive integers with the property that the product of any two distinct members of $A$ will not exceed 1994. Show that there are numbers $a$ and $b$ in the set $A$ such that the gcd of $a$ and $b$ is greater than 1.
5 replies
Rushil
Oct 25, 2005
SomeonecoolLovesMaths
3 hours ago
Solve the system
Rushil   20
N 3 hours ago by SomeonecoolLovesMaths
Source: 0
Solve the system of equations for real $x$ and $y$: \begin{eqnarray*} 5x \left( 1 + \frac{1}{x^2 + y^2}\right) &=& 12 \\ 5y \left( 1 - \frac{1}{x^2+y^2} \right) &=& 4 . \end{eqnarray*}
20 replies
Rushil
Oct 25, 2005
SomeonecoolLovesMaths
3 hours ago
Angles made with the median
BBNoDollar   1
N 4 hours ago by Ianis
Determine the measures of the angles of triangle \(ABC\), knowing that the median \(BM\) makes an angle of \(30^\circ\) with side \(AB\) and an angle of \(15^\circ\) with side \(BC\).
1 reply
BBNoDollar
5 hours ago
Ianis
4 hours ago
Find all rationals s.t..
Rushil   12
N 4 hours ago by SomeonecoolLovesMaths
Source: Indian RMO 1994 Problem 7
Find the number of rationals $\frac{m}{n}$ such that

(i) $0 < \frac{m}{n} < 1$;

(ii) $m$ and $n$ are relatively prime;

(iii) $mn = 25!$.
12 replies
Rushil
Oct 25, 2005
SomeonecoolLovesMaths
4 hours ago
interesting function equation (fe) in IR
skellyrah   2
N Apr 23, 2025 by jasperE3
Source: mine
find all function F: IR->IR such that $$ xf(f(y)) + yf(f(x)) = f(xf(y)) + f(xy) $$
2 replies
skellyrah
Apr 23, 2025
jasperE3
Apr 23, 2025
interesting function equation (fe) in IR
G H J
Source: mine
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skellyrah
25 posts
#1
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find all function F: IR->IR such that $$ xf(f(y)) + yf(f(x)) = f(xf(y)) + f(xy) $$
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CrazyInMath
459 posts
#2
Y by
solution
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jasperE3
11364 posts
#4
Y by
skellyrah wrote:
find all function F: IR->IR such that $$ xf(f(y)) + yf(f(x)) = f(xf(y)) + f(xy) $$

If IR means irrational numbers, and the problem is to find all $f$ such that $xf(f(y)) + yf(f(x)) = f(xf(y)) + f(xy)$ for all $x,y\in\mathbb{IR}$ then setting $x=f(y)^{-1}$ gives a contradiction
This post has been edited 1 time. Last edited by jasperE3, Apr 23, 2025, 9:43 PM
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