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In Cyclic Quadrilateral ABCD, find AB^2+BC^2-CD^2-AD^2
Darealzolt   0
an hour ago
Source: KTOM April 2025 P8
Given Cyclic Quadrilateral \(ABCD\) with an area of \(2025\), with \(\angle ABC = 45^{\circ}\). If \( 2AC^2 = AB^2+BC^2+CD^2+DA^2\), Hence find the value of \(AB^2+BC^2-CD^2-DA^2\).
0 replies
Darealzolt
an hour ago
0 replies
Interesting inequality
sqing   0
2 hours ago
Source: Own
Let $  a, b,c>0,b+c\geq 3a$. Prove that
$$ \sqrt{\frac{a}{b+c-a}}-\frac{ 2a^2-b^2-c^2}{(a+b)(a+c)}\geq \frac{2}{5}+\frac{1}{\sqrt 2}$$$$ \frac{3}{2}\sqrt{\frac{a}{b+c-a}}-\frac{ 2a^2-b^2-c^2}{(a+b)(a+c)}\geq \frac{2}{5}+\frac{3}{2\sqrt 2}$$
0 replies
sqing
2 hours ago
0 replies
Inspired by m4thbl3nd3r
sqing   4
N 3 hours ago by sqing
Source: Own
Let $  a, b,c>0,b+c>a$. Prove that$$\sqrt{\frac{a}{b+c-a}}-\frac{2a^2-b^2-c^2}{(a+b)(a+c)}\geq 1$$$$\frac{a}{b+c-a}-\frac{2a^2-b^2-c^2}{(a+b)(a+c)} \geq  \frac{4\sqrt 2}{3}-1$$
4 replies
sqing
Yesterday at 3:43 AM
sqing
3 hours ago
Not so beautiful
m4thbl3nd3r   3
N 3 hours ago by m4thbl3nd3r
Let $a, b,c>0$ such that $b+c>a$. Prove that $$2 \sqrt[4]{\frac{a}{b+c-a}}\ge 2 +\frac{2a^2-b^2-c^2}{(a+b)(a+c)}.$$
3 replies
m4thbl3nd3r
Yesterday at 3:23 AM
m4thbl3nd3r
3 hours ago
Inequality by Po-Ru Loh
v_Enhance   57
N 3 hours ago by Learning11
Source: ELMO 2003 Problem 4
Let $x,y,z \ge 1$ be real numbers such that \[ \frac{1}{x^2-1} + \frac{1}{y^2-1} + \frac{1}{z^2-1} = 1. \] Prove that \[ \frac{1}{x+1} + \frac{1}{y+1} + \frac{1}{z+1} \le 1. \]
57 replies
v_Enhance
Dec 29, 2012
Learning11
3 hours ago
Inspired by Darealzolt
sqing   0
4 hours ago
Source: Own
Let $ a,b,c\geq 1$ and $ a^2+b^2+c^2+abc=\frac{9}{2}. $ Prove that
$$3\left(\sqrt[3] 2+\frac{1}{\sqrt[3] 2} -1\right) \geq a+b+c\geq  \frac{3+\sqrt{11}}{2}$$$$\frac{3}{2}\left(4+\sqrt[3] 4-\sqrt[3] 2\right) \geq a+b+c+ab+bc+ca\geq  \frac{3(1+\sqrt{11})}{2}$$
0 replies
sqing
4 hours ago
0 replies
2024 IMO P1
EthanWYX2009   104
N 4 hours ago by SYBARUPEMULA
Source: 2024 IMO P1
Determine all real numbers $\alpha$ such that, for every positive integer $n,$ the integer
$$\lfloor\alpha\rfloor +\lfloor 2\alpha\rfloor +\cdots +\lfloor n\alpha\rfloor$$is a multiple of $n.$ (Note that $\lfloor z\rfloor$ denotes the greatest integer less than or equal to $z.$ For example, $\lfloor -\pi\rfloor =-4$ and $\lfloor 2\rfloor= \lfloor 2.9\rfloor =2.$)

Proposed by Santiago Rodríguez, Colombia
104 replies
EthanWYX2009
Jul 16, 2024
SYBARUPEMULA
4 hours ago
2-var inequality
sqing   8
N 4 hours ago by sqing
Source: Own
Let $ a,b>0 , a^2+b^2-ab\leq 1 . $ Prove that
$$a^3+b^3 -\frac{a^4}{b+1}  -\frac{b^4}{a+1} \leq 1 $$
8 replies
sqing
May 27, 2025
sqing
4 hours ago
ai+aj is the multiple of n
Jackson0423   0
4 hours ago

Consider an increasing sequence of integers \( a_n \).
For every positive integer \( n \), there exist indices \( 1 \leq i < j \leq n \) such that \( a_i + a_j \) is divisible by \( n \).
Given that \( a_1 \geq 1 \), find the minimum possible value of \( a_{100} \).
0 replies
Jackson0423
4 hours ago
0 replies
Addition on the IMO
naman12   139
N 5 hours ago by ezpotd
Source: IMO 2020 Problem 1
Consider the convex quadrilateral $ABCD$. The point $P$ is in the interior of $ABCD$. The following ratio equalities hold:
\[\angle PAD:\angle PBA:\angle DPA=1:2:3=\angle CBP:\angle BAP:\angle BPC\]Prove that the following three lines meet in a point: the internal bisectors of angles $\angle ADP$ and $\angle PCB$ and the perpendicular bisector of segment $AB$.

Proposed by Dominik Burek, Poland
139 replies
naman12
Sep 22, 2020
ezpotd
5 hours ago
IMO ShortList 1998, number theory problem 5
orl   66
N 6 hours ago by lksb
Source: IMO ShortList 1998, number theory problem 5
Determine all positive integers $n$ for which there exists an integer $m$ such that ${2^{n}-1}$ is a divisor of ${m^{2}+9}$.
66 replies
orl
Oct 22, 2004
lksb
6 hours ago
ANGLE EQUAL
PrimeSol   7
N Aug 3, 2016 by jayme
O -circumcenter, H - ortocenter and (OD) perpendicular (DE).
Prove that angle(DHE)=angle(ABC).
7 replies
PrimeSol
Nov 26, 2015
jayme
Aug 3, 2016
ANGLE EQUAL
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PrimeSol
175 posts
#1 • 1 Y
Y by Adventure10
O -circumcenter, H - ortocenter and (OD) perpendicular (DE).
Prove that angle(DHE)=angle(ABC).
Attachments:
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kormidscoler
64 posts
#2 • 2 Y
Y by Adventure10, Mango247
BUTTERFLY THEOREM
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jayme
9801 posts
#3 • 1 Y
Y by Adventure10
Dear Mathlinkers,
very nice idea...

Sincerely
Jean-Louis
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PrimeSol
175 posts
#4 • 2 Y
Y by Adventure10, Mango247
kormidscoler ?
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Gryphos
1702 posts
#5 • 2 Y
Y by PrimeSol, Adventure10
Slightly more detailed solution with Butterfly theorem
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jayme
9801 posts
#6 • 2 Y
Y by PrimeSol, Adventure10
Dear Mathlinkers,
if you like butterflies, you can see

http://jl.ayme.pagesperso-orange.fr/Docs/Papillon.pdf

Sincerely
Jean-Louis
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armpist
527 posts
#7 • 2 Y
Y by Adventure10, Mango247
Dear MLs,



M.T.
This post has been edited 2 times. Last edited by armpist, Mar 24, 2017, 7:29 PM
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jayme
9801 posts
#8 • 2 Y
Y by Adventure10, Mango247
Dear Mathlinkers,
just an interesting link with

http://www.artofproblemsolving.com/community/c6t48f6h1283140_two_perpendiculars

Sincerely
Jean-Louis
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