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pretty well known
dotscom26   0
13 minutes ago
Let $\triangle ABC$ be a scalene triangle such that $\Omega$ is its incircle. $AB$ is tangent to $\Omega$ at $D$. A point $E$ ($E \notin \Omega$) is located on $BC$.

Let $\omega_1$, $\omega_2$, and $\omega_3$ be the incircles of the triangles $BED$, $ADE$, and $AEC$, respectively.

Show that the common tangent to $\omega_1$ and $\omega_3$ is also tangent to $\omega_2$.

0 replies
dotscom26
13 minutes ago
0 replies
Modular NT
oVlad   3
N 26 minutes ago by EVKV
Source: Romania JBMO TST 2024 Day 1 P1
Find all the positive integers $a{}$ and $b{}$ such that $(7^a-5^b)/8$ is a prime number.

Cosmin Manea and Dragoș Petrică
3 replies
+1 w
oVlad
Jul 31, 2024
EVKV
26 minutes ago
Ratio conditions; prove angle XPA = angle AQY
MellowMelon   15
N 31 minutes ago by cj13609517288
Source: USA TSTST 2011/2012 P2
Two circles $\omega_1$ and $\omega_2$ intersect at points $A$ and $B$. Line $\ell$ is tangent to $\omega_1$ at $P$ and to $\omega_2$ at $Q$ so that $A$ is closer to $\ell$ than $B$. Let $X$ and $Y$ be points on major arcs $\overarc{PA}$ (on $\omega_1$) and $AQ$ (on $\omega_2$), respectively, such that $AX/PX = AY/QY = c$. Extend segments $PA$ and $QA$ through $A$ to $R$ and $S$, respectively, such that $AR = AS = c\cdot PQ$. Given that the circumcenter of triangle $ARS$ lies on line $XY$, prove that $\angle XPA = \angle AQY$.
15 replies
MellowMelon
Jul 26, 2011
cj13609517288
31 minutes ago
IMO 2017 Problem 1
cjquines0   154
N 43 minutes ago by blueprimes
Source: IMO 2017 Problem 1
For each integer $a_0 > 1$, define the sequence $a_0, a_1, a_2, \ldots$ for $n \geq 0$ as
$$a_{n+1} = 
\begin{cases}
\sqrt{a_n} & \text{if } \sqrt{a_n} \text{ is an integer,} \\
a_n + 3 & \text{otherwise.}
\end{cases}
$$Determine all values of $a_0$ such that there exists a number $A$ such that $a_n = A$ for infinitely many values of $n$.

Proposed by Stephan Wagner, South Africa
154 replies
cjquines0
Jul 18, 2017
blueprimes
43 minutes ago
IMO 2018 Problem 5
orthocentre   76
N an hour ago by Maximilian113
Source: IMO 2018
Let $a_1$, $a_2$, $\ldots$ be an infinite sequence of positive integers. Suppose that there is an integer $N > 1$ such that, for each $n \geq N$, the number
$$\frac{a_1}{a_2} + \frac{a_2}{a_3} + \cdots + \frac{a_{n-1}}{a_n} + \frac{a_n}{a_1}$$is an integer. Prove that there is a positive integer $M$ such that $a_m = a_{m+1}$ for all $m \geq M$.

Proposed by Bayarmagnai Gombodorj, Mongolia
76 replies
orthocentre
Jul 10, 2018
Maximilian113
an hour ago
Is this FE solvable?
Mathdreams   3
N an hour ago by jasperE3
Find all $f:\mathbb{R} \rightarrow \mathbb{R}$ such that \[f(2x+y) + f(x+f(2y)) = f(x)f(y) - xy\]for all reals $x$ and $y$.
3 replies
Mathdreams
Tuesday at 6:58 PM
jasperE3
an hour ago
Junior Balkan Mathematical Olympiad 2024- P3
Lukaluce   13
N an hour ago by EVKV
Source: JBMO 2024
Find all triples of positive integers $(x, y, z)$ that satisfy the equation

$$2020^x + 2^y = 2024^z.$$
Proposed by Ognjen Tešić, Serbia
13 replies
Lukaluce
Jun 27, 2024
EVKV
an hour ago
Geometry :3c
popop614   2
N 2 hours ago by Ianis
Source: MINE :<
Quadrilateral $ABCD$ has an incenter $I$ Suppose $AB > BC$. Let $M$ be the midpoint of $AC$. Suppose that $MI \perp BI$. $DI$ meets $(BDM)$ again at point $T$. Let points $P$ and $Q$ be such that $T$ is the midpoint of $MP$ and $I$ is the midpoint of $MQ$. Point $S$ lies on the plane such that $AMSQ$ is a parallelogram, and suppose the angle bisectors of $MCQ$ and $MSQ$ concur on $IM$.

The angle bisectors of $\angle PAQ$ and $\angle PCQ$ meet $PQ$ at $X$ and $Y$. Prove that $PX = QY$.
2 replies
popop614
2 hours ago
Ianis
2 hours ago
cursed tangent is xiooix
TestX01   2
N 3 hours ago by TestX01
Source: xiooix and i
Let $ABC$ be a triangle. Let $E$ and $F$ be the intersections of the $B$ and $C$ angle bisectors with the opposite sides. Let $S = (AEF) \cap (ABC)$. Let $W = SL \cap (AEF)$ where $L$ is the major $BC$ arc midpiont.
i)Show that points $S , B , C , W , E$ and $F$ are coconic on a conic $\mathcal{C}$
ii) If $\mathcal{C}$ intersects $(ABC)$ again at $T$, not equal to $B,C$ or $S$, then prove $AL$ and $ST$ concur on $(AEF)$

I will post solution in ~1 week if noone solves.
2 replies
TestX01
Feb 25, 2025
TestX01
3 hours ago
Game on a row of 9 squares
EmersonSoriano   2
N 3 hours ago by Mr.Sharkman
Source: 2018 Peru TST Cono Sur P10
Let $n$ be a positive integer. Alex plays on a row of 9 squares as follows. Initially, all squares are empty. In each turn, Alex must perform exactly one of the following moves:

$(i)\:$ Choose a number of the form $2^j$, with $j$ a non-negative integer, and place it in an empty square.

$(ii)\:$ Choose two (not necessarily consecutive) squares containing the same number, say $2^j$. Replace the number in one of the squares with $2^{j+1}$ and erase the number in the other square.

At the end of the game, one square contains the number $2^n$, while the other squares are empty. Determine, as a function of $n$, the maximum number of turns Alex can make.
2 replies
EmersonSoriano
4 hours ago
Mr.Sharkman
3 hours ago
Guessing Point is Hard
MarkBcc168   30
N 3 hours ago by Circumcircle
Source: IMO Shortlist 2023 G5
Let $ABC$ be an acute-angled triangle with circumcircle $\omega$ and circumcentre $O$. Points $D\neq B$ and $E\neq C$ lie on $\omega$ such that $BD\perp AC$ and $CE\perp AB$. Let $CO$ meet $AB$ at $X$, and $BO$ meet $AC$ at $Y$.

Prove that the circumcircles of triangles $BXD$ and $CYE$ have an intersection lie on line $AO$.

Ivan Chan Kai Chin, Malaysia
30 replies
MarkBcc168
Jul 17, 2024
Circumcircle
3 hours ago
Geometry
noway   5
N Dec 15, 2019 by Sugiyem
$\triangle ABC$ inscribe $(O)$. $M,N,P$ is the midpoint of $BC,CA,AB$. $S_a$ is the intersection of the tangent of $(O)$ at $B$ and $C$. The tangent of $(O)$ at $A$ intersects $NP$ at $R_a$. Simillarity, we have $S_b,S_c,R_b,R_c$.
Prove that $(OS_aR_a), (OS_bR_b), (OS_cR_c)$ have second common point (not $O$).
IMAGE
5 replies
noway
Dec 5, 2019
Sugiyem
Dec 15, 2019
Geometry
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noway
332 posts
#1 • 2 Y
Y by Adventure10, Mango247
$\triangle ABC$ inscribe $(O)$. $M,N,P$ is the midpoint of $BC,CA,AB$. $S_a$ is the intersection of the tangent of $(O)$ at $B$ and $C$. The tangent of $(O)$ at $A$ intersects $NP$ at $R_a$. Simillarity, we have $S_b,S_c,R_b,R_c$.
Prove that $(OS_aR_a), (OS_bR_b), (OS_cR_c)$ have second common point (not $O$).
https://scontent.fdad1-1.fna.fbcdn.net/v/t1.15752-9/78417712_450594615642658_6055837001834299392_n.png?_nc_cat=100&_nc_ohc=cNSRtfWdFN4AQkduZDt7O1IXrF7agAP1jNlhtrM7dkj6hraY2lwUpOteg&_nc_ht=scontent.fdad1-1.fna&oh=711383ec4e0f0c76299ab1c96572e1f5&oe=5E42B99C
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LKira
252 posts
#2 • 1 Y
Y by Adventure10
My geogebra say no, it not true, may you check again your problem ?
This post has been edited 1 time. Last edited by LKira, Dec 5, 2019, 8:52 AM
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noway
332 posts
#3 • 1 Y
Y by Adventure10
LKira wrote:
My geogebra say no, it not true, may you check again your problem ?

I have checked carefully, it's true ^^
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LKira
252 posts
#4 • 1 Y
Y by Adventure10
noway wrote:
LKira wrote:
My geogebra say no, it not true, may you check again your problem ?

I have checked carefully, it's true ^^

Then see VMO 2018 P7
This post has been edited 1 time. Last edited by LKira, Dec 5, 2019, 2:26 PM
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ancamagelqueme
104 posts
#5 • 2 Y
Y by Adventure10, Mango247
Your second common point of the three circles has the first baricentric coordinate

a^2 (2 a^16-6 a^14 (b^2+c^2)+a^12 (-4 b^4+38 b^2 c^2-4 c^4)+2 a^10 (9 b^6-20 b^4 c^2-20 b^2 c^4+9 c^6)+a^8 (-67 b^6 c^2+174 b^4 c^4-67 b^2 c^6)+4 a^4 (b^2-c^2)^2 (b^8+9 b^6 c^2-32 b^4 c^4+9 b^2 c^6+c^8)-(b^4-c^4)^2 (2 b^8-9 b^6 c^2+10 b^4 c^4-9 b^2 c^6+2 c^8)+2 a^2 (b^2-c^2)^2 (3 b^10-18 b^8 c^2+11 b^6 c^4+11 b^4 c^6-18 b^2 c^8+3 c^10)-2 a^6 (9 b^10-51 b^8 c^2+46 b^6 c^4+46 b^4 c^6-51 b^2 c^8+9 c^10))

This triangle center is not currently in https://faculty.evansville.edu/ck6/encyclopedia/ETC.html
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Sugiyem
115 posts
#6 • 2 Y
Y by Adventure10, Mango247
Is this correct?

We begin with the main claim
$\textbf{Claim}$: Given a $\triangle ABC$ and point $P$ on its euler line. Let line $AP$,$BP$,$CP$ intersect the $\odot ABC$ again at $A'$,$B'$, and $C'$ respectively. Define $D,E,F$ to be the midpoint of $BC$,$AC$ and $AB$ respectively and define also $X$,$Y$,$Z$ to be the midpont of $AA'$,$BB'$ and $CC'$ respectively. Then we have that $DX$,$EY$ and $FZ$ are concurrent.

$\textbf{Proof}$:
Animate point $P$ on the euler line, therefore we will get that the degree of point $A',B',C'$ are all 2. Hence the degree of $X,Y,Z$ are also 2. Since point $D,E,F$ are all fixed we must have that the degree of line $DX,EY,FZ$ are all 2. So if we want to prove that $DX,EY,FZ$ are concurrent we only need to check that for $2+2+2+1=7$ possibilities of point $P$, $DX,EY,FZ$ are always concurrent. It's easy to check that for $P$ is the circumcenter, centroid the two intersections of euler line with the circumcircle of $ABC$, intersection of euler line with $BC$,$CA$,$AB$, the three lines $DX,EY,FZ$ always concurrent. Therefore, $\textbf{QED}$

We go back to the original problem
Define $X_{a},X_{b},X_{c}$ be the point on $(O)$ different from $A,B,C$ such that $X_{a}R_{a}$, $X_{b}R_{b}$ and $X_{c}R_{c}$ are all tangent to $(O)$. Now define $Y_{a},Y_{b},Y_{c}$ to be the midpoint of $AX_{a}$, $BX_{b}$ and $CY_{c}$ respectively.
Invert the figure WRT to $(O)$, then the original problem is equivalent to proving that $MY_{a}$,$NY_{b}$ and $PY_{c}$ are concur at one point.
However, it's a classic result from IMO 2011 G4 that $AX_{a},BX_{b}$ and $CX_{c}$ are concurrent at point $W$, the isogonal conjugate of isotomic conjugate of orthocenter $H$ of $\triangle ABC$. Moreover it's well known that this point $W$ is on the euler line. Therefore by the first claim, the problem is done.
This post has been edited 5 times. Last edited by Sugiyem, Dec 23, 2019, 10:11 PM
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