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AD=BE implies ABC right
v_Enhance   115
N 18 minutes ago by Adywastaken
Source: European Girl's MO 2013, Problem 1
The side $BC$ of the triangle $ABC$ is extended beyond $C$ to $D$ so that $CD = BC$. The side $CA$ is extended beyond $A$ to $E$ so that $AE = 2CA$. Prove that, if $AD=BE$, then the triangle $ABC$ is right-angled.
115 replies
v_Enhance
Apr 10, 2013
Adywastaken
18 minutes ago
Geometry
gggzul   6
N 22 minutes ago by Captainscrubz
In trapezoid $ABCD$ segments $AB$ and $CD$ are parallel. Angle bisectors of $\angle A$ and $\angle C$ meet at $P$. Angle bisectors of $\angle B$ and $\angle D$ meet at $Q$. Prove that $ABPQ$ is cyclic
6 replies
gggzul
Yesterday at 8:22 AM
Captainscrubz
22 minutes ago
Need help on this simple looking problem
TheGreatEuler   0
27 minutes ago
Show that 1+2+3+4....n divides 1^k+2^k+3^k....n^k when k is odd. Is this possible to prove without using congruence modulo or binomial coefficients?
0 replies
TheGreatEuler
27 minutes ago
0 replies
Geometry
Lukariman   5
N an hour ago by Lukariman
Given circle (O) and point P outside (O). From P draw tangents PA and PB to (O) with contact points A, B. On the opposite ray of ray BP, take point M. The circle circumscribing triangle APM intersects (O) at the second point D. Let H be the projection of B on AM. Prove that $\angle HDM$ = 2∠AMP.
5 replies
Lukariman
Yesterday at 12:43 PM
Lukariman
an hour ago
inq , not two of them =0
win14   0
an hour ago
Let a,b,c be non negative real numbers such that no two of them are simultaneously equal to 0
$$\frac{1}{a + b} + \frac{1}{b + c} + \frac{1}{c + a} \ge \frac{5}{2\sqrt{ab + bc + ca}}.$$
0 replies
1 viewing
win14
an hour ago
0 replies
IMO Genre Predictions
ohiorizzler1434   62
N an hour ago by ehuseyinyigit
Everybody, with IMO upcoming, what are you predictions for the problem genres?


Personally I predict: predict
62 replies
ohiorizzler1434
May 3, 2025
ehuseyinyigit
an hour ago
Number theory
MathsII-enjoy   5
N 2 hours ago by MathsII-enjoy
Prove that when $x^p+y^p$ | $(p^2-1)^n$ with $x,y$ are positive integers and $p$ is prime ($p>3$), we get: $x=y$
5 replies
MathsII-enjoy
Monday at 3:22 PM
MathsII-enjoy
2 hours ago
Number theory
Foxellar   0
2 hours ago
It is known that for all positive integers $k$,
\[
1^2 + 2^2 + 3^2 + \ldots + k^2 = \frac{k(k + 1)(2k + 1)}{6}
\]Find the smallest positive integer $k$ such that $1^2 + 2^2 + 3^2 + \ldots + k^2$ is divisible by 200.
0 replies
Foxellar
2 hours ago
0 replies
Combinatorics
P162008   4
N 2 hours ago by cazanova19921
Let $m,n \in \mathbb{N}.$ Let $[n]$ denote the set of natural numbers less than or equal to $n.$

Let $f(m,n) = \sum_{(x_1,x_2,x_3, \cdots, x_m) \in [n]^{m}} \frac{x_1}{x_1 + x_2 + x_3 + \cdots + x_m} \binom{n}{x_1} \binom{n}{x_2} \binom{n}{x_3} \cdots \binom{n}{x_m} 2^{\left(\sum_{i=1}^{m} x_i\right)}$

Compute the sum of the digits of $f(4,4).$
4 replies
P162008
Today at 5:38 AM
cazanova19921
2 hours ago
Aime type Geo
ehuseyinyigit   4
N 2 hours ago by ehuseyinyigit
Source: Turkish First Round 2024
In a scalene triangle $ABC$, let $M$ be the midpoint of side $BC$. Let the line perpendicular to $AC$ at point $C$ intersect $AM$ at $N$. If $(BMN)$ is tangent to $AB$ at $B$, find $AB/MA$.
4 replies
ehuseyinyigit
Monday at 9:04 PM
ehuseyinyigit
2 hours ago
n variables with n-gon sides
mihaig   1
N 2 hours ago by mihaig
Source: Own
Let $n\geq3$ and let $a_1,a_2,\ldots, a_n\geq0$ be reals such that $\sum_{i=1}^{n}{\frac{1}{2a_i+n-2}}=1.$
Prove
$$\frac{24}{(n-1)(n-2)}\cdot\sum_{1\leq i<j<k\leq n}{a_ia_ja_k}\geq3\sum_{i=1}^{n}{a_i}+n.$$
1 reply
mihaig
Apr 25, 2025
mihaig
2 hours ago
T lies on Euler circle
ken3k06   6
N Jun 1, 2022 by jayme
Let $\displaystyle ABC$ be a triangle with altitudes $\displaystyle AD,BE,CF$ intersect at orthocenter $\displaystyle H$. Let $\displaystyle T$ be an arbitrary point lies on $\displaystyle ( DEF)$. $\displaystyle D'$ be the reflection point of $\displaystyle D$ on $\displaystyle AT$. $\displaystyle D'T$ intersects $\displaystyle EF$ at $\displaystyle P$. Prove that $\displaystyle ( DTP)$ passes through the circumcenter of $\displaystyle ADP$.

IMAGE
6 replies
ken3k06
May 25, 2022
jayme
Jun 1, 2022
T lies on Euler circle
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G H BBookmark kLocked kLocked NReply
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ken3k06
424 posts
#1
Y by
Let $\displaystyle ABC$ be a triangle with altitudes $\displaystyle AD,BE,CF$ intersect at orthocenter $\displaystyle H$. Let $\displaystyle T$ be an arbitrary point lies on $\displaystyle ( DEF)$. $\displaystyle D'$ be the reflection point of $\displaystyle D$ on $\displaystyle AT$. $\displaystyle D'T$ intersects $\displaystyle EF$ at $\displaystyle P$. Prove that $\displaystyle ( DTP)$ passes through the circumcenter of $\displaystyle ADP$.

https://scontent.fdad3-1.fna.fbcdn.net/v/t1.15752-9/280650918_1427756197694764_7145749033231498711_n.png?_nc_cat=103&ccb=1-7&_nc_sid=ae9488&_nc_ohc=FnjTOESeskgAX_1wK43&_nc_ht=scontent.fdad3-1.fna&oh=03_AVLcP-KSAuX1yT9QQnr-7uA5KQKqpYNK3FAoMz3bkSIasQ&oe=62B1F047
This post has been edited 1 time. Last edited by ken3k06, May 25, 2022, 1:38 AM
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jayme
9792 posts
#2 • 1 Y
Y by ken3k06
Any ideas?

Sincerely
Jean-Louis
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VZH
60 posts
#3 • 1 Y
Y by ken3k06
Hints:
We only need to prove $\angle PTD= 2\angle PAD$, and because $D$ and $D'$ are symmetric wrt $AT$, it suffices to show $(ATP)$ is tangent to $AD$.
Consider an inversion wrt $A$ that swaps $(B,F)$ and $(D,E)$. Now, this inversion sends $P, T$ to $P', T'$, where $P'$ and $T'$ lie on $(ABC)$ and $(BHC)$ respectively. Let $H'$ be the reflection of $H$ on $AT$, then the inversion also swaps $(H',D')$, and so $A,T',G',H'$ are concyclic. From here, proving $T'G' \parallel AD$ is easy.
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jayme
9792 posts
#4 • 2 Y
Y by ken3k06, Mango247
Dear,
thank you for your proof...
Do you have an idea for a synthetic proof without inversion?

Sincerely
Jean-Louis
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jayme
9792 posts
#5 • 1 Y
Y by ken3k06
Bump!

Sincerely
Jean-Louis
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jayme
9792 posts
#6 • 1 Y
Y by ken3k06
last Bump!

Sincerely
Jean-Louis
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jayme
9792 posts
#7
Y by
Dear Mathlinkersn
finally I have found a proof...

Any references?

Thank in advance
Sincerely
Jean-Louis
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