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Geometry
Lukariman   3
N an hour ago by Lukariman
Given circle (O) and point P outside (O). From P draw tangents PA and PB to (O) with contact points A, B. On the opposite ray of ray BP, take point M. The circle circumscribing triangle APM intersects (O) at the second point D. Let H be the projection of B on AM. Prove that $\angle HDM$ = 2∠AMP.
3 replies
Lukariman
Yesterday at 12:43 PM
Lukariman
an hour ago
USAMO 2003 Problem 1
MithsApprentice   68
N 2 hours ago by Mamadi
Prove that for every positive integer $n$ there exists an $n$-digit number divisible by $5^n$ all of whose digits are odd.
68 replies
MithsApprentice
Sep 27, 2005
Mamadi
2 hours ago
Centroid, altitudes and medians, and concyclic points
BR1F1SZ   3
N 2 hours ago by EeEeRUT
Source: Austria National MO Part 1 Problem 2
Let $\triangle{ABC}$ be an acute triangle with $BC > AC$. Let $S$ be the centroid of triangle $ABC$ and let $F$ be the foot of the perpendicular from $C$ to side $AB$. The median $CS$ intersects the circumcircle $\gamma$ of triangle $\triangle{ABC}$ at a second point $P$. Let $M$ be the point where $CS$ intersects $AB$. The line $SF$ intersects the circle $\gamma$ at a point $Q$, such that $F$ lies between $S$ and $Q$. Prove that the points $M,P,Q$ and $F$ lie on a circle.

(Karl Czakler)
3 replies
BR1F1SZ
Monday at 9:45 PM
EeEeRUT
2 hours ago
IMO Genre Predictions
ohiorizzler1434   60
N 2 hours ago by Yiyj
Everybody, with IMO upcoming, what are you predictions for the problem genres?


Personally I predict: predict
60 replies
ohiorizzler1434
May 3, 2025
Yiyj
2 hours ago
square root problem
kjhgyuio   5
N 2 hours ago by Solar Plexsus
........
5 replies
kjhgyuio
May 3, 2025
Solar Plexsus
2 hours ago
Diodes and usamons
v_Enhance   47
N 2 hours ago by EeEeRUT
Source: USA December TST for the 56th IMO, by Linus Hamilton
A physicist encounters $2015$ atoms called usamons. Each usamon either has one electron or zero electrons, and the physicist can't tell the difference. The physicist's only tool is a diode. The physicist may connect the diode from any usamon $A$ to any other usamon $B$. (This connection is directed.) When she does so, if usamon $A$ has an electron and usamon $B$ does not, then the electron jumps from $A$ to $B$. In any other case, nothing happens. In addition, the physicist cannot tell whether an electron jumps during any given step. The physicist's goal is to isolate two usamons that she is sure are currently in the same state. Is there any series of diode usage that makes this possible?

Proposed by Linus Hamilton
47 replies
v_Enhance
Dec 17, 2014
EeEeRUT
2 hours ago
3-var inequality
sqing   1
N 3 hours ago by sqing
Source: Own
Let $ a,b\geq  0 ,a^3-ab+b^3=1  $. Prove that
$$  \frac{1}{2}\geq     \frac{a}{a^2+3 }+ \frac{b}{b^2+3}   \geq  \frac{1}{4}$$$$  \frac{1}{2}\geq     \frac{a}{a^3+3 }+ \frac{b}{b^3+3}   \geq  \frac{1}{4}$$$$  \frac{1}{2}\geq \frac{a}{a^2+ab+2}+ \frac{b}{b^2+ ab+2}  \geq  \frac{1}{3}$$$$  \frac{1}{2}\geq \frac{a}{a^3+ab+2}+ \frac{b}{b^3+ ab+2}  \geq  \frac{1}{3}$$Let $ a,b\geq  0 ,a^3+ab+b^3=3  $. Prove that
$$  \frac{1}{2}\geq     \frac{a}{a^2+3 }+ \frac{b}{b^2+3}   \geq  \frac{1}{4}(\frac{1}{\sqrt[3]{3}}+\sqrt[3]{3}-1)$$$$  \frac{1}{2}\geq     \frac{a}{a^3+3 }+ \frac{b}{b^3+3}   \geq  \frac{1}{2\sqrt[3]{9}}$$$$  \frac{1}{2}\geq \frac{a}{a^2+ab+2}+ \frac{b}{b^2+ ab+2}  \geq  \frac{4\sqrt[3]{3}+3\sqrt[3]{9}-6}{17}$$$$  \frac{1}{2}\geq \frac{a}{a^3+ab+2}+ \frac{b}{b^3+ ab+2}  \geq  \frac{\sqrt[3]{3}}{5}$$
1 reply
sqing
3 hours ago
sqing
3 hours ago
IMO ShortList 2001, combinatorics problem 3
orl   37
N 3 hours ago by deduck
Source: IMO ShortList 2001, combinatorics problem 3, HK 2009 TST 2 Q.2
Define a $ k$-clique to be a set of $ k$ people such that every pair of them are acquainted with each other. At a certain party, every pair of 3-cliques has at least one person in common, and there are no 5-cliques. Prove that there are two or fewer people at the party whose departure leaves no 3-clique remaining.
37 replies
orl
Sep 30, 2004
deduck
3 hours ago
area of O_1O_2O_3O_4 <=1, incenters of right triangles outside a square
parmenides51   2
N 3 hours ago by Solilin
Source: Thailand Mathematical Olympiad 2012 p4
Let $ABCD$ be a unit square. Points $E, F, G, H$ are chosen outside $ABCD$ so that $\angle AEB =\angle BF C = \angle CGD = \angle DHA = 90^o$ . Let $O_1, O_2, O_3, O_4$, respectively, be the incenters of $\vartriangle ABE, \vartriangle BCF, \vartriangle CDG, \vartriangle DAH$. Show that the area of $O_1O_2O_3O_4$ is at most $1$.
2 replies
parmenides51
Aug 17, 2020
Solilin
3 hours ago
Geo metry
TUAN2k8   3
N 3 hours ago by TUAN2k8
Help me plss!
Given an acute triangle $ABC$. Points $D$ and $E$ lie on segments $AB$ and $AC$, respectively. Lines $BD$ and $CE$ intersect at point $F$. The circumcircles of triangles $BDF$ and $CEF$ intersect at a second point $P$. The circumcircles of triangles $ABC$ and $ADE$ intersect at a second point $Q$. Point $K$ lies on segment $AP$ such that $KQ \perp AQ$. Prove that triangles $\triangle BKD$ and $\triangle CKE$ are similar.
3 replies
TUAN2k8
Yesterday at 10:33 AM
TUAN2k8
3 hours ago
Functional equation of nonzero reals
proglote   8
N 4 hours ago by jasperE3
Source: Brazil MO 2013, problem #3
Find all injective functions $f\colon \mathbb{R}^* \to \mathbb{R}^* $ from the non-zero reals to the non-zero reals, such that \[f(x+y) \left(f(x) + f(y)\right) = f(xy)\] for all non-zero reals $x, y$ such that $x+y \neq 0$.
8 replies
proglote
Oct 24, 2013
jasperE3
4 hours ago
complex bashing in angles??
megahertz13   2
N Apr 18, 2025 by ali123456
Source: 2013 PUMAC FA2
Let $\gamma$ and $I$ be the incircle and incenter of triangle $ABC$. Let $D$, $E$, $F$ be the tangency points of $\gamma$ to $\overline{BC}$, $\overline{CA}$, $\overline{AB}$ and let $D'$ be the reflection of $D$ about $I$. Assume $EF$ intersects the tangents to $\gamma$ at $D$ and $D'$ at points $P$ and $Q$. Show that $\angle DAD' + \angle PIQ = 180^\circ$.
2 replies
megahertz13
Nov 5, 2024
ali123456
Apr 18, 2025
complex bashing in angles??
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G H BBookmark kLocked kLocked NReply
Source: 2013 PUMAC FA2
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megahertz13
3183 posts
#1 • 1 Y
Y by Rayanelba
Let $\gamma$ and $I$ be the incircle and incenter of triangle $ABC$. Let $D$, $E$, $F$ be the tangency points of $\gamma$ to $\overline{BC}$, $\overline{CA}$, $\overline{AB}$ and let $D'$ be the reflection of $D$ about $I$. Assume $EF$ intersects the tangents to $\gamma$ at $D$ and $D'$ at points $P$ and $Q$. Show that $\angle DAD' + \angle PIQ = 180^\circ$.
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TestX01
341 posts
#2
Y by
Polars or Lahire gives that $IQ\perp AD'$, $AD\perp IP$. Let $PI\cap DQ=X$. We claim $\triangle AD'D\sim\triangle IQX$. This follows from $\angle IDA=\angle DPI=\angle QXI$, and $180^\circ-\angle AD'I=180^\circ-\angle IQX$ from the perpendiculars.

The similarity easily finishes.
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ali123456
52 posts
#3 • 1 Y
Y by Rayanelba
My solution
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