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Product is a perfect square( very easy)
Nuran2010   1
N 15 minutes ago by SomeonecoolLovesMaths
Source: Azerbaijan Junior National Olympiad 2021 P1
At least how many numbers must be deleted from the product $1 \times 2 \times \dots \times 22 \times 23$ in order to make it a perfect square?
1 reply
Nuran2010
2 hours ago
SomeonecoolLovesMaths
15 minutes ago
smo 2018 open 2nd round q2
dominicleejun   7
N 21 minutes ago by Kyj9981
Let O be a point inside triangle ABC such that $\angle BOC$ is $90^\circ$ and $\angle BAO = \angle BCO$. Prove that $\angle OMN$ is $90$ degrees, where $M$ and $N$ are the midpoints of $\overline{AC}$ and $\overline{BC}$, respectively.
7 replies
dominicleejun
Aug 15, 2019
Kyj9981
21 minutes ago
inequalities
Cobedangiu   4
N 26 minutes ago by Nguyenhuyen_AG
$a,b,c>0$ and $\sum ab=\dfrac{1}{3}$. Prove that:
$\sum \dfrac{1}{a^2-bc+1}\le 3$
4 replies
Cobedangiu
Today at 4:06 AM
Nguyenhuyen_AG
26 minutes ago
Solution needed ASAP
UglyScientist   6
N 42 minutes ago by UglyScientist
$ABC$ is acute triangle. $H$ is orthocenter, $M$ is the midpoint of $BC$, $L$ is the midpoint of smaller arc $BC$. Point $K$ is on $AH$ such that, $MK$ is perpendicular to $AL$. Prove that: $HMLK$ is paralelogram(Synthetic sol needed).
6 replies
UglyScientist
2 hours ago
UglyScientist
42 minutes ago
Two equal angles
jayme   2
N an hour ago by jayme
Dear Mathlinkers,

1. ABCD a square
2. I the midpoint of AB
3. 1 the circle center at A passing through B
4. Q the point of intersection of 1 with the segment IC
5. X the foot of the perpendicular to BC from Q
6. Y the point of intersection of 1 with the segment AX
7. M the point of intersection of CY and AB.

Prove : <ACI = <IYM.

Sincerely
Jean-Louis
2 replies
jayme
Yesterday at 6:52 AM
jayme
an hour ago
minimum of \sqrt{\frac{a}{b(3a+2)}}+\sqrt{\frac{b}{a(3b+2)}}
parmenides51   11
N an hour ago by sqing
Source: JBMO Shortlist 2017 A2
Let $a$ and $b$ be positive real numbers such that $3a^2 + 2b^2 = 3a + 2b$. Find the minimum value of $A =\sqrt{\frac{a}{b(3a+2)}} + \sqrt{\frac{b}{a(2b+3)}} $
11 replies
parmenides51
Jul 25, 2018
sqing
an hour ago
Inequality
MathsII-enjoy   0
an hour ago
A interesting problem generalized :-D
0 replies
MathsII-enjoy
an hour ago
0 replies
Interesting inequalities
sqing   1
N 2 hours ago by sqing
Source: Own
Let $ a,b,c>0 $ and $ (a+b)^2 (a+c)^2=16abc. $ Prove that
$$ 2a+b+c\leq \frac{128}{27}$$$$ \frac{9}{2}a+b+c\leq \frac{864}{125}$$$$3a+b+c\leq 24\sqrt{3}-36$$$$5a+b+c\leq \frac{4(8\sqrt{6}-3)}{9}$$
1 reply
sqing
Yesterday at 2:35 PM
sqing
2 hours ago
Geometry Problem
Euler_Gauss   0
2 hours ago
Given that $D$ is the midpoint of $BC$, $DM$ bisects $\angle ADB$ and intersects $AB$ at $M$, $I$ is the incenter of $\triangle {}{}{}ABD$, $AT$ bisects $\angle BAC$ and intersects the circumcircle of \(\triangle {}{}ABC\) at $T$, $MS$ is parallel to $BC$ and intersects $AT$ at $S$. Prove that $\angle MIS + \angle BIT = \pi.$
0 replies
Euler_Gauss
2 hours ago
0 replies
Tricky invariant with 3 numbers on the board
Nuran2010   0
2 hours ago
Source: Azerbaijan Junior National Olympiad 2021
Initially, the numbers $1,1,-1$ written on the board.At every step,Mikail chooses the two numbers $a,b$ and substitutes them with $2a+c$ and $\frac{b-c}{2}$ where $c$ is the unchosen number on the board. Prove that at least $1$ negative number must be remained on the board at any step.
0 replies
Nuran2010
2 hours ago
0 replies
Two circles and Three line concurrency
mofidy   0
Apr 10, 2025
Two circles $W_1$ and $W_2$ with equal radii intersect at P and Q. Points B and C are located on the circles$W_1$ and $W_2$ so that they are inside the circles $W_2$ and $W_1$, respectively. Also, points X and Y distinct from P are located on $W_1$ and $W_2$, respectively, so that:
$$\angle{CPQ} = \angle{CXQ}  \text{ and } \angle{BPQ} = \angle{BYQ}.$$The intersection point of the circumcircles of triangles XPC and YPB is called S. Prove that BC, XY and QS are concurrent.
Thanks.
0 replies
mofidy
Apr 10, 2025
0 replies
Two circles and Three line concurrency
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mofidy
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Two circles $W_1$ and $W_2$ with equal radii intersect at P and Q. Points B and C are located on the circles$W_1$ and $W_2$ so that they are inside the circles $W_2$ and $W_1$, respectively. Also, points X and Y distinct from P are located on $W_1$ and $W_2$, respectively, so that:
$$\angle{CPQ} = \angle{CXQ}  \text{ and } \angle{BPQ} = \angle{BYQ}.$$The intersection point of the circumcircles of triangles XPC and YPB is called S. Prove that BC, XY and QS are concurrent.
Thanks.
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