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|a^2-b^2-2abc|<2c implies abc EVEN!
tom-nowy   1
N an hour ago by Tkn
Source: Own
Prove that if integers $a, b$ and $c$ satisfy $\left| a^2-b^2-2abc \right| <2c $, then $abc$ is an even number.
1 reply
tom-nowy
May 3, 2025
Tkn
an hour ago
Tricky inequality
Orestis_Lignos   28
N an hour ago by MR.1
Source: JBMO 2023 Problem 2
Prove that for all non-negative real numbers $x,y,z$, not all equal to $0$, the following inequality holds

$\displaystyle \dfrac{2x^2-x+y+z}{x+y^2+z^2}+\dfrac{2y^2+x-y+z}{x^2+y+z^2}+\dfrac{2z^2+x+y-z}{x^2+y^2+z}\geq 3.$

Determine all the triples $(x,y,z)$ for which the equality holds.

Milan Mitreski, Serbia
28 replies
Orestis_Lignos
Jun 26, 2023
MR.1
an hour ago
JBMO Shortlist 2023 A1
Orestis_Lignos   5
N an hour ago by MR.1
Source: JBMO Shortlist 2023, A1
Prove that for all positive real numbers $a,b,c,d$,

$$\frac{2}{(a+b)(c+d)+(b+c)(a+d)} \leq \frac{1}{(a+c)(b+d)+4ac}+\frac{1}{(a+c)(b+d)+4bd}$$
and determine when equality occurs.
5 replies
Orestis_Lignos
Jun 28, 2024
MR.1
an hour ago
square root problem
kjhgyuio   6
N an hour ago by kjhgyuio
........
6 replies
kjhgyuio
May 3, 2025
kjhgyuio
an hour ago
find angle
TBazar   5
N an hour ago by TBazar
Given $ABC$ triangle with $AC>BC$. We take $M$, $N$ point on AC, AB respectively such that $AM=BC$, $CM=BN$. $BM$, $AN$ lines intersect at point $K$. If $2\angle AKM=\angle ACB$, find $\angle ACB$
5 replies
TBazar
Yesterday at 6:57 AM
TBazar
an hour ago
2 var inquality
Iveela   19
N 2 hours ago by sqing
Source: Izho 2025 P1
Let $a, b$ be positive reals such that $a^3 + b^3 = ab + 1$. Prove that \[(a-b)^2 + a + b \geq 2\]
19 replies
Iveela
Jan 14, 2025
sqing
2 hours ago
Set of perfect powers is irreducible
Assassino9931   0
2 hours ago
Source: Al-Khwarizmi International Junior Olympiad 2025 P4
For two sets of integers $X$ and $Y$ we define $X\cdot Y$ as the set of all products of an element of $X$ and an element of $Y$. For example, if $X=\{1, 2, 4\}$ and $Y=\{3, 4, 6\}$ then $X\cdot Y=\{3, 4, 6, 8, 12, 16, 24\}.$ We call a set $S$ of positive integers good if there do not exist sets $A,B$ of positive integers, each with at least two elements and such that the sets $A\cdot B$ and $S$ are the same. Prove that the set of perfect powers greater than or equal to $2025$ is good.

(In any of the sets $A$, $B$, $A\cdot B$ no two elements are equal, but any two or three of these sets may have common elements. A perfect power is an integer of the form $n^k$, where $n>1$ and $k > 1$ are integers.)

Lajos Hajdu and Andras Sarkozy, Hungary
0 replies
Assassino9931
2 hours ago
0 replies
Al-Khwarizmi birth year in a combi process
Assassino9931   0
2 hours ago
Source: Al-Khwarizmi International Junior Olympiad 2025 P3
On a circle are arranged $100$ baskets, each containing at least one candy. The total number of candies is $780$. Asad and Sevinch make moves alternatingly, with Asad going first. On one move, Asad takes all the candies from $9$ consecutive non-empty baskets, while Sevinch takes all the candies from a single non-empty basket that has at least one empty neighboring basket. Prove that Asad can take overall at least $700$ candies, regardless of the initial distribution of candies and Sevinch's actions.

Shubin Yakov, Russia
0 replies
Assassino9931
2 hours ago
0 replies
Grouping angles in a pentagon with bisectors
Assassino9931   0
2 hours ago
Source: Al-Khwarizmi International Junior Olympiad 2025 P2
Let $ABCD$ be a convex quadrilateral with \[\angle ADC = 90^\circ, \ \ \angle BCD = \angle ABC > 90^\circ, \mbox{ and } AB = 2CD.\]The line through \(C\), parallel to \(AD\), intersects the external angle bisector of \(\angle ABC\) at point \(T\). Prove that the angles $\angle ATB$, $\angle TBC$, $\angle BCD$, $\angle CDA$, $\angle DAT$ can be divided into two groups, so that the angles in each group have a sum of $270^{\circ}$.

Miroslav Marinov, Bulgaria
0 replies
Assassino9931
2 hours ago
0 replies
Nice Functional Equations (ISI 2021)
integrated_JRC   11
N 2 hours ago by lakshya2009
Source: ISI 2021 P2
Let $f : \mathbb{Z} \to \mathbb{Z}$ be a function satisfying $f(0) \neq 0 = f(1)$. Assume also that $f$ satisfies equations (A) and (B) below. \begin{eqnarray*}f(xy) = f(x) + f(y) -f(x) f(y)\qquad\mathbf{(A)}\\
f(x-y) f(x) f(y) = f(0) f(x) f(y)\qquad\mathbf{(B)}
\end{eqnarray*}for all integers $x,y$.

(i) Determine explicitly the set $\big\{f(a)~:~a\in\mathbb{Z}\big\}$.
(ii) Assuming that there is a non-zero integer $a$ such that $f(a) \neq 0$, prove that the set $\big\{b~:~f(b) \neq 0\big\}$ is infinite.
11 replies
integrated_JRC
Jul 18, 2021
lakshya2009
2 hours ago
A Generalization of Ptolemy's Theorem
buratinogigle   0
Apr 16, 2025
Source: VN Math Olympiad For High School Students P7 - 2025
Given a convex quadrilateral $ABCD$, define
\[
\alpha = |\angle ADB - \angle ACB| = |\angle DAC - \angle DBC|  
\quad\text{and}\quad  
\beta = |\angle ABD - \angle ACD| = |\angle BAC - \angle BDC|.
\]Prove that
\[
AC \cdot BD = AD \cdot BC \cos\alpha + AB \cdot CD \cos\beta.
\]
0 replies
buratinogigle
Apr 16, 2025
0 replies
A Generalization of Ptolemy's Theorem
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Source: VN Math Olympiad For High School Students P7 - 2025
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buratinogigle
2372 posts
#1
Y by
Given a convex quadrilateral $ABCD$, define
\[
\alpha = |\angle ADB - \angle ACB| = |\angle DAC - \angle DBC|  
\quad\text{and}\quad  
\beta = |\angle ABD - \angle ACD| = |\angle BAC - \angle BDC|.
\]Prove that
\[
AC \cdot BD = AD \cdot BC \cos\alpha + AB \cdot CD \cos\beta.
\]
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