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- 2 KB (337 words) - 13:56, 25 June 2023
- ...rst exams in the series of exams used to challenge bright students, grades 10 and below, on the path towards choosing the team that represents the United High scoring AMC 10 and AMC 12 students are invited to take the [[American Invitational Mathema4 KB (586 words) - 16:48, 28 October 2024
- 2 KB (332 words) - 08:37, 30 December 2021
- [[AMC 10]] problems and solutions. | colspan="2"| [[2001 AMC 10 | AMC 10]]2 KB (249 words) - 22:22, 13 July 2024
- 4 KB (731 words) - 16:59, 4 January 2022
- [[2021 JMC 10 Problems/Problem 1|Solution]] [[2021 JMC 10 Problems/Problem 2|Solution]]12 KB (1,784 words) - 15:49, 1 April 2021
- 977 bytes (156 words) - 12:57, 19 January 2021
- ...ms|2006 AMC 12A #10]] and [[2006 AMC 10A Problems/Problem 10|2006 AMC 10A #10]]}} ...bf{(A) } 3\qquad \textbf{(B) } 6\qquad \textbf{(C) } 9\qquad \textbf{(D) } 10\qquad \textbf{(E) } 11</math>.1 KB (167 words) - 00:27, 26 September 2024
- {{duplicate|[[2005 AMC 12B Problems|2005 AMC 12B #10]] and [[2005 AMC 10B Problems|2005 AMC 10B #11]]}} == Problem 10 ==1 KB (204 words) - 06:10, 5 November 2024
- 3 KB (436 words) - 19:35, 13 August 2024
- #REDIRECT [[2006 AMC 12A Problems/Problem 10]]46 bytes (5 words) - 09:56, 20 February 2016
- 5 KB (852 words) - 20:23, 4 October 2023
- [[Image:2004_I_AIME-10.png]] [[Image:2004_I_AIME-10.png]]5 KB (836 words) - 06:53, 15 October 2023
- 8 KB (1,283 words) - 18:19, 8 May 2024
- ...possible sequences with one digit repeated twice, and then divide by <math>10</math>. ...> sequences of length <math>4</math> with one digit repeated. We divide by 10 to get <math>\boxed{432}</math> as our answer.5 KB (855 words) - 19:26, 14 January 2023
- ...r base numbers is <math>21.</math> Hence, our maximum number is <math>21 + 10 = 31.</math> [https://youtu.be/RdbzOJNGFd0?si=wmSC0FGm1lqfW63J 1984 AIME #10]7 KB (1,181 words) - 00:53, 21 November 2024
- ...answer will be 100 times the number of integers we can reach between 1 and 10. ...nteger. If we let <math>x = \frac 12</math> then we get the solution <math>10</math>; now consider when <math>x < \frac 12</math>: <math>\lfloor 2x \rflo12 KB (1,859 words) - 17:16, 28 March 2022
- ...</math>, <math>b</math>, and <math>c</math> represent digits in base <math>10</math> in the order indicated. The magician then asks this person to form t3 KB (565 words) - 15:51, 1 October 2023
- ...amount of steps is <math>150 - 10r = 75 + 15r</math>. Al is getting <math>10</math> seconds of resistance at rate <math>r</math> from the escalator, whi7 KB (1,187 words) - 15:21, 27 January 2024
- 6 KB (906 words) - 12:25, 19 November 2024
Page text matches
- A = (-10,10); B = (10,10);5 KB (885 words) - 22:03, 5 October 2024
- ...\ 6 \qquad (\mathrm {C})\ 8 \qquad (\mathrm {D}) \ 9 \qquad (\mathrm {E})\ 10 </math>2 KB (307 words) - 23:58, 17 November 2024
- For what value of <math>x</math> does <math>10^{x}\cdot 100^{2x}=1000^{5}</math>? We can rewrite <math>10^{x}\cdot 100^{2x}=1000^{5}</math> as <math>10^{5x}=10^{15}</math>:1 KB (190 words) - 09:58, 16 June 2023
- ...digit and 2 appears 3 times as a units digit, the answer is <math>10\cdot 10+1\cdot 3=\boxed{\textbf{(D) }103.}</math>967 bytes (143 words) - 02:18, 27 June 2023
- ...extbf{(B)}\ 7\qquad\textbf{(C)}\ 8\qquad\textbf{(D)}\ 9\qquad\textbf{(E)}\ 10</math> Notice that <math>1 + 2 + 3 \cdots + 10 = 55.</math> Knowing this, we can say that <math>11 + 12 \cdots + 20 = 155<2 KB (315 words) - 14:34, 18 June 2022
- {{AMC10 box|year=2016|ab=A|num-b=10|num-a=12}}8 KB (1,016 words) - 23:17, 30 December 2023
- **[[AMC 10]]5 KB (608 words) - 08:32, 17 November 2024
- * [[Technology for Youth Empowerment - AMC 10 Program this Fall 2023]] (Zoom) [https://docs.google.com/forms/d/e/1FAIpQLS14 KB (1,881 words) - 18:07, 22 October 2024
- * National Science Foundation's Robert Noyce Scholarship. <dollar/>10,000 for undergraduate or graduate students studying to become math or scien * National Science Foundation's Robert Noyce Scholarship. <dollar/>10,000 for undergraduate or graduate students studying to become math or scien7 KB (851 words) - 09:54, 29 January 2022
- ** In it's first year (2009-2010), the 10 finalists were all named Proton Energy Scholars and given <math>\textdollar894 bytes (123 words) - 14:48, 13 June 2022
- ...problems are usually the easiest problems in the competition, and the last 10 problems can be as hard as some of the Team Round questions. No calculators 10 problems in 20 minutes for a team of 4 students. These problems typically i10 KB (1,505 words) - 17:51, 4 October 2024
- ...</math> is the base-4 representation of <math>2013</math>, and <math>2013_{10}=133131</math>, so the answer is <math>1+3+3+1+3+1=\boxed{12}</math>.190 bytes (26 words) - 05:13, 16 February 2024
- ...at each grade level after the third contest results are tabulated. The top 10 schools at each grade level will receive certificates and be recognized in ...ts of 20 questions, to be completed in two 30 minute time periods. The top 10 individual scores from each school will count for the school total.8 KB (1,182 words) - 13:26, 3 April 2024
- ...]], (grades 5-12). It is divided into three divisions, grades 5-6, 7-9 and 10-12, and is a 40 minute, 5 question test. First, second and third in each di3 KB (473 words) - 15:11, 16 June 2020
- | [https://www.maa.org/sites/default/files/pdf/AMC/usamo/10-Qual_list2.pdf Martin Camacho, Rohit Agrawal, Gaurav Singh] | [https://www.maa.org/sites/default/files/pdf/AMC/usamo/10-JMO-Qual_list2.pdf Isaac Bohart, Kevin Lu]5 KB (724 words) - 11:09, 21 November 2024
- ...all offers the AMC 10/12. OSSM offers the AMC 12. Whittier offers the AMC 10. ...a Math League], which is part of the math league (mathleague.com). Around 10 high schools in Oklahoma participates in it.2 KB (279 words) - 18:41, 23 March 2017
- ...physical estimation competition. Grades 4-9 compete in this format. Grades 10-12 are slightly different.2 KB (216 words) - 15:59, 17 December 2016
- ...tagi's [https://www.tmasacademy.com/ace-the-amc10-12-free-book ACE The AMC 10 and 12 book] Mastering AMC 10/12: https://www.omegalearn.org/mastering-amc101216 KB (2,192 words) - 22:06, 19 July 2024
- The Alabama [[MathCounts]] team has achieved numerous top 10 finishes at the National MathCounts competition and won the national champi The Alabama MathCounts team has placed in the top 10 at the national competition numerous times and won the national championshi3 KB (386 words) - 20:23, 6 May 2023
- ...commended for students grades who are participating in contests like AMC 8/10 and Mathcounts. * Intermediate is recommended for students who can expect to pass the AMC 10/12.24 KB (3,182 words) - 10:10, 31 August 2024
