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Create the page "15!!!" on this wiki! See also the search results found.
Page title matches
- 6 KB (910 words) - 19:31, 24 October 2023
- 3 KB (458 words) - 16:40, 6 October 2019
- 919 bytes (138 words) - 12:45, 4 August 2017
- 2 KB (411 words) - 21:02, 21 December 2020
- 3 KB (532 words) - 17:49, 13 August 2023
- </asy></center><!-- Asymptote replacement for Image:2005_I_AIME-15.png by azjps -->5 KB (906 words) - 23:15, 6 January 2024
- D((0,30)--(0,-10),Arrows(4));D((15,0)--(-25,0),Arrows(4));D((0,0)--MP("y=ax",(14,14 * (69/100)^.5),E),EndArrow [[Image:2005_AIME_II_-15.png||center|800px]]12 KB (2,000 words) - 13:17, 28 December 2020
- 15&2^{13}-4\cdot 7\\ 17&2^{15}-16\cdot 9\\9 KB (1,491 words) - 01:23, 26 December 2022
- <cmath>s_{13, 4} = 2s_{15 - 13, 3} + 1 = 2s_{2, 3}+1</cmath> (46,15)&64&16\\6 KB (899 words) - 20:58, 12 May 2022
- <!-- [[Image:1983_AIME-15.png|200px]] --> <cmath>0 \geq f(3) = 25 - 15\cos \alpha - 20 \sin \alpha</cmath>19 KB (3,221 words) - 01:05, 7 February 2023
- \frac{x^2}{15}+\frac{y^2}{7}-\frac{z^2}{9}-\frac{w^2}{33}=1\\ \frac{x^2}{63}+\frac{y^2}{55}+\frac{z^2}{39}+\frac{w^2}{15}=1\\6 KB (1,050 words) - 18:07, 16 January 2024
- [[Image:AIME 1985 Problem 15.png]]2 KB (245 words) - 22:44, 4 March 2024
- <math>2a^2 + 5b^2 = - \frac {15}{2}ab \ \ \ \ (2)</math></div>11 KB (1,722 words) - 09:49, 13 September 2023
- 5 KB (838 words) - 18:05, 19 February 2022
- 7 KB (1,186 words) - 10:16, 4 June 2023
- ...ac{[APC] + [BPC]}{[APB]} = 3</math>, so <math>CP = \dfrac{3}{4} \cdot CF = 15</math>. ...ed out, so <math>w_C = 1</math> and <math>w_F = 3</math>. Thus, <math>CP = 15</math> and <math>PF = 5</math>.13 KB (2,091 words) - 00:20, 26 October 2023
- 4 KB (644 words) - 16:24, 28 May 2023
- 4 KB (658 words) - 16:58, 10 November 2023
- 3 KB (445 words) - 22:01, 20 August 2022
- 2 KB (358 words) - 01:54, 2 October 2020
Page text matches
- <cmath>8-15-17</cmath>5 KB (886 words) - 21:12, 22 January 2024
- {{AMC12 box|year=2005|num-b=15|num-a=17|ab=A}}2 KB (307 words) - 15:30, 30 March 2024
- ...an rewrite <math>10^{x}\cdot 100^{2x}=1000^{5}</math> as <math>10^{5x}=10^{15}</math>: 10^{5x} & =10^{15}1 KB (190 words) - 10:58, 16 June 2023
- &= \frac{3}{8}-\left(-\frac{2}{5}\right)\left\lfloor\frac{-15}{16}\right\rfloor\\2 KB (257 words) - 10:57, 16 June 2023
- label("$1$",(15/2,0),dir(270)); label("$1$",(15/2,0),dir(270));8 KB (1,016 words) - 00:17, 31 December 2023
- {{AMC10 box|year=2016|ab=A|num-b=15|num-a=17}}1 KB (235 words) - 14:52, 25 June 2023
- ...age or mathematical development, had its first year in 2015, and grew from 15 attendees in 2015 to 31 attendees in 2023.5 KB (706 words) - 23:49, 29 January 2024
- The contest is given in-school May 1-15. Each school sets its own testing date and time within these guidelines.8 KB (1,182 words) - 14:26, 3 April 2024
- ...roblems from the [[UK Junior Mathematical Olympiad]], for students ages 11-15.24 KB (3,177 words) - 12:53, 20 February 2024
- **School receives $15,0004 KB (623 words) - 13:11, 20 February 2024
- *Achievement Roll: Awarded to students in 6th or younger who score 15 points or higher on the AMC 8. Awarded to students in 8th or younger who sc *AIME floor: 81 (top ~15%)17 KB (1,921 words) - 13:00, 28 April 2024
- \\x+5-13+4x+20&\ge 3x+1512 KB (1,798 words) - 16:20, 14 March 2023
- ...>: 3<br><u>Problem 6-10</u>: 4<br><u>Problem 10-12</u>: 5<br><u>Problem 12-15</u>: 6}} ...hile correct answers receive one point of credit, making the maximum score 15. Problems generally increase in difficulty as the exam progresses - the fi8 KB (1,057 words) - 12:02, 25 February 2024
- ...roblems from the [[UK Junior Mathematical Olympiad]], for students ages 11-15.2 KB (302 words) - 16:45, 3 October 2019
- See the [[How to join an ARML team]] wiki page for more info. Teams have 15 students.2 KB (267 words) - 17:06, 7 March 2020
- ...The three top teams usually all place in the top 20, often even in the top 15 or 10. ...or is selected, although it does happen. Then the coaches select the best 15 young students (10th grade and below) to comprise a C team -- a team specif21 KB (3,500 words) - 18:41, 23 April 2024
- Students must be current 10-11th graders who will be 15-17 years old on the first day of the program. The cost is \$6500.1 KB (166 words) - 17:54, 10 June 2016
- ...the equations, we have the solutions as <math>\boxed{(5, 25), (24, 6), (6, 15), (14, 7), (8, 10), (9, 9)}</math>.7 KB (1,107 words) - 07:35, 26 March 2024
- # Prove that having 100 whole numbers, one can choose 15 of them so that the difference of any two is divisible by 7. ([[Pigeonhole11 KB (1,985 words) - 21:03, 5 August 2023
- 15 take algebra, language arts, social studies, and history. 15 take algebra, language arts, biology, and history.9 KB (1,703 words) - 07:25, 24 March 2024
