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• 2004 AIME I Problems/Problem 4
  ...h is <math>4-\pi \approx 0.86</math>, so <math>100k = \boxed{086}</math>. ~Extremelysupercooldude
  3 KB (532 words) - 08:22, 11 July 2023
• 1996 AIME Problems/Problem 5
  ~Extremelysupercooldude
  3 KB (585 words) - 18:39, 8 September 2024
• 2005 AMC 10A Problems/Problem 10
  ~Extremelysupercooldude (Second solution)
  3 KB (450 words) - 19:33, 13 September 2024
• 2011 AMC 10B Problems/Problem 23
  -Extremelysupercooldude: In your solution, you find the hundreds digit of <math>2011^{11}</math>, b
  9 KB (1,288 words) - 19:47, 13 June 2024
• 2012 AMC 10A Problems/Problem 20
  ...rom there, your chances of guessing the right answer are slightly higher. ~Extremelysupercooldude
  6 KB (1,016 words) - 18:55, 6 October 2024
• 2012 AMC 10A Problems/Problem 18
  ...final answer. Thus, the only possible solution is <math>\boxed{E}</math>. ~Extremelysupercooldude
  6 KB (931 words) - 13:53, 3 November 2024
• 2012 AMC 12B Problems/Problem 3
  ...answer choices, we see that <math>\boxed{\textbf{(D)}\ 48}</math> works. ~Extremelysupercooldude
  907 bytes (144 words) - 06:12, 29 June 2023
• 2012 AMC 12B Problems/Problem 4
  ...as <math>\boxed{ \textbf{(B)} \ 4 }</math> percent more money than Diana. ~Extremelysupercooldude
  1 KB (155 words) - 06:18, 29 June 2023
• 2012 AMC 12B Problems/Problem 5
  ...ven integer is required. The answer is <math>\boxed{\textbf{(A)}}</math>. ~Extremelysupercooldude (Latex, grammar, and solution edits)
  2 KB (332 words) - 06:28, 29 June 2023
• 2012 AMC 12B Problems/Problem 6
  ...inal <math>x - y</math>. The answer is <math>\boxed{\textbf{(A)}}</math>. ~Extremelysupercooldude
  1 KB (246 words) - 06:32, 29 June 2023
• 2012 AMC 12B Problems/Problem 9
  ~Extremelysupercooldude (Latex edits) ...would take her <math>\boxed{\textbf{(B)}\ 40}</math> seconds to get down. ~Extremelysupercooldude
  2 KB (341 words) - 07:14, 29 June 2023
• 2014 AMC 12A Problems/Problem 10
  ~Extremelysupercooldude
  3 KB (439 words) - 02:10, 23 January 2023
• 2015 AIME II Problems/Problem 4
  Thus, <math>p + q = 16 + 2 = \boxed{18}</math>. ~Extremelysupercooldude
  5 KB (766 words) - 13:17, 28 June 2023
• 2016 AMC 12A Problems/Problem 23
  ~Extremelysupercooldude
  10 KB (1,700 words) - 15:49, 16 May 2024
• 2020 AMC 10B Problems/Problem 14
  --Extremelysupercooldude (Minor latex and grammar edits)
  17 KB (2,384 words) - 12:04, 13 October 2024
• 2021 AMC 12A Problems/Problem 3
  ~Extremelysupercooldude (Minor grammar edits)
  4 KB (673 words) - 20:35, 26 December 2023
• 2021 AMC 12B Problems/Problem 16
  -Extremelysupercooldude (Minor Latex Edits and Grammar)
  4 KB (720 words) - 09:02, 1 October 2023