Difference between revisions of "2019 AMC 10B Problems/Problem 12"

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Note: the number can also be <math>5566_7</math>, which will also give the answer of <math>22</math>.
 
Note: the number can also be <math>5566_7</math>, which will also give the answer of <math>22</math>.
  
iron
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iron  
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Edited by greersc
 
Edited by greersc
  

Revision as of 17:15, 14 February 2019

Problem

What is the greatest possible sum of the digits in the base-seven representation of a positive integer less than $2019$?

$\textbf{(A) } 11 \qquad\textbf{(B) } 14 \qquad\textbf{(C) } 22 \qquad\textbf{(D) } 23 \qquad\textbf{(E) } 27$

Solution

Convert $2019$ to base $7$. This will get you $5613_7$, which will be the upper bound. To maximize the sum of the digits, we want as many $6$s as possible (which is the highest value in base $7$), and this would be the number $4666_7$. Thus, the answer is $4+6+6+6 = \boxed{C) 22}$

Note: the number can also be $5566_7$, which will also give the answer of $22$.

iron

Edited by greersc

See Also

2019 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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