Difference between revisions of "2019 AMC 8 Problems/Problem 11"
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==Solution 1== | ==Solution 1== | ||
| + | Let <math>x</math> be the number of students taking both a math and a foreign language class. | ||
| + | By P-I-E, we get <math>70 + 54 - x</math> = <math>93</math>. | ||
| + | |||
| + | Solving gives us <math>x = 31</math>. | ||
| + | |||
| + | But we want the number of students taking only a math class. | ||
| + | |||
| + | Which is <math>70 - 31 = 39</math>. | ||
| + | |||
| + | <math>\boxed{\textbf{(D)}\ 39}</math> | ||
| + | |||
| + | ~phoenixfire | ||
==See Also== | ==See Also== | ||
Revision as of 12:52, 20 November 2019
Problem 11
The eighth grade class at Lincoln Middle School has 
students. Each student takes a math class or a foreign language class or both. There are 
eigth graders taking a math class, and there are 
eight graders taking a foreign language class. How many eigth graders take 
a math class and 
a foreign language class?
Solution 1
Let 
be the number of students taking both a math and a foreign language class.
By P-I-E, we get 
= .
Solving gives us 
.
But we want the number of students taking only a math class.
Which is 
.
~phoenixfire
See Also
| 2019 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
