Difference between revisions of "2023 AMC 12B Problems/Problem 4"
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+ | {{duplicate|[[2023 AMC 10B Problems/Problem 4|2023 AMC 10B #4]] and [[2023 AMC 12B Problems/Problem 4|2023 AMC 12B #4]]}} | ||
+ | ==Problem== | ||
+ | Jackson's paintbrush makes a narrow strip with a width of <math>6.5</math> millimeters. Jackson has enough paint to make a strip <math>25</math> meters long. How many square centimeters of paper could Jackson cover with paint? | ||
+ | |||
+ | <math>\textbf{(A) } 162,500 \qquad\textbf{(B) } 162.5 \qquad\textbf{(C) }1,625 \qquad\textbf{(D) }1,625,000 \qquad\textbf{(E) } 16,250</math> | ||
+ | |||
+ | ==Solution 1== | ||
+ | <math>6.5</math> millimeters is equal to <math>0.65</math> centimeters. <math>25</math> meters is <math>2500</math> centimeters. The answer is <math>0.65 \times 2500</math>, so the answer is <math>\boxed{\textbf{(C) 1,625}}</math>. | ||
+ | |||
+ | ~Failure.net | ||
+ | |||
+ | ==Solution 2 (Scientific Form)== | ||
+ | <math>6.5</math> millimeters can be represented as <math>65 \times 10^{-2}</math> centimeters. <math>25</math> meters is <math>25 \times 10^{2}</math> centimeters. Multiplying out these results in <math>(65 \times 10^{-2}) \times (25 \times 10^{2})</math>, which is <math>65 \times 25</math> making the answer <math>\boxed{\textbf{(C) 1,625}}</math>. | ||
+ | |||
+ | ~darrenn.cp | ||
+ | |||
+ | ==Video Solution 1 by SpreadTheMathLove== | ||
+ | |||
+ | https://www.youtube.com/watch?v=SUnhwbA5_So | ||
+ | |||
+ | ==Video Solution by Math-X (First understand the problem!!!)== | ||
+ | https://youtu.be/EuLkw8HFdk4?si=mEwHK_VyAr1h0O1A&t=808 | ||
+ | |||
+ | ~Math-X | ||
+ | |||
+ | ==Video Solution== | ||
+ | |||
+ | https://youtu.be/BZ1zeFvw5hU | ||
+ | |||
+ | |||
+ | ~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com) | ||
+ | |||
+ | ==Video Solution by Interstigation== | ||
+ | https://youtu.be/gDnmvcOzxjg?si=cYB6uChy7Ue0UT4L | ||
+ | |||
+ | ==See also== | ||
+ | {{AMC10 box|year=2023|ab=B|num-b=3|num-a=5}} | ||
+ | {{AMC12 box|year=2023|ab=B|num-b=3|num-a=5}} | ||
+ | {{MAA Notice}} |
Latest revision as of 15:39, 21 November 2023
- The following problem is from both the 2023 AMC 10B #4 and 2023 AMC 12B #4, so both problems redirect to this page.
Contents
Problem
Jackson's paintbrush makes a narrow strip with a width of millimeters. Jackson has enough paint to make a strip meters long. How many square centimeters of paper could Jackson cover with paint?
Solution 1
millimeters is equal to centimeters. meters is centimeters. The answer is , so the answer is .
~Failure.net
Solution 2 (Scientific Form)
millimeters can be represented as centimeters. meters is centimeters. Multiplying out these results in , which is making the answer .
~darrenn.cp
Video Solution 1 by SpreadTheMathLove
https://www.youtube.com/watch?v=SUnhwbA5_So
Video Solution by Math-X (First understand the problem!!!)
https://youtu.be/EuLkw8HFdk4?si=mEwHK_VyAr1h0O1A&t=808
~Math-X
Video Solution
~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com)
Video Solution by Interstigation
https://youtu.be/gDnmvcOzxjg?si=cYB6uChy7Ue0UT4L
See also
2023 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2023 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 3 |
Followed by Problem 5 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.