Difference between revisions of "2010 AMC 12A Problems/Problem 1"

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== Problem 1 ==
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== Problem ==
 
What is <math>\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)</math>?
 
What is <math>\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)</math>?
  
 
<math>\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 401 \qquad \textbf{(E)}\ 4020</math>
 
<math>\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 401 \qquad \textbf{(E)}\ 4020</math>
  
[[2010 AMC 12A Problems/Problem 1|Solution]]
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== Solution ==
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<math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>.
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==Video Solution==
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https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_
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~Charles3829
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== See Also ==
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{{AMC12 box|year=2010|before=First Problem|num-a=2|ab=A}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 09:53, 18 September 2024

Problem

What is $\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)$?

$\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 401 \qquad \textbf{(E)}\ 4020$

Solution

$20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}$.

Video Solution

https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_

~Charles3829

See Also

2010 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
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All AMC 12 Problems and Solutions

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