Difference between revisions of "2007 iTest Problems/Problem 51"

(Created page with "== Problem == Find the highest point (largest possible <math>y</math>-coordinate) on the parabola <cmath>y=-2x^2+ 28x+ 418</cmath> == Solution ==")
 
(Solution to Problem 51 - easy!)
 
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== Solution ==
 
== Solution ==
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One way to find the highest point is to rewrite the quadratic into vertex form.
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<cmath>y = -2(x^2 - 14x - 209)</cmath>
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Complete the square inside the parentheses.
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<cmath>y = -2(x^2 - 14x + 49 - 49 - 209)</cmath>
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<cmath>y = -2((x-7)^2 - 258)</cmath>
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<cmath>y = -2(x-7)^2 + 516</cmath>
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Thus, the largest possible y-coordinate is <math>\boxed{516}</math>.
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==See Also==
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{{iTest box|year=2007|num-b=50|num-a=52}}
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[[Category:Introductory Algebra Problems]]

Latest revision as of 18:59, 16 June 2018

Problem

Find the highest point (largest possible $y$-coordinate) on the parabola \[y=-2x^2+ 28x+ 418\]

Solution

One way to find the highest point is to rewrite the quadratic into vertex form. \[y = -2(x^2 - 14x - 209)\] Complete the square inside the parentheses. \[y = -2(x^2 - 14x + 49 - 49 - 209)\] \[y = -2((x-7)^2 - 258)\] \[y = -2(x-7)^2 + 516\] Thus, the largest possible y-coordinate is $\boxed{516}$.

See Also

2007 iTest (Problems, Answer Key)
Preceded by:
Problem 50
Followed by:
Problem 52
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