Difference between revisions of "2007 iTest Problems/Problem 29"
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Let <math>S</math> be equal to the sum <math>1+2+3+\cdots+2007</math>. Find the remainder when <math>S</math> is divided by <math>1000</math>. | Let <math>S</math> be equal to the sum <math>1+2+3+\cdots+2007</math>. Find the remainder when <math>S</math> is divided by <math>1000</math>. | ||
− | == Solution == | + | ==Solution== |
+ | |||
+ | The list of numbers is an [[arithmetic sequence]] with <math>2007</math> terms, first term <math>1</math>, and last term <math>2007</math>. Using the arithmetic series sum formula, <math>S = \frac{2007(1+2007)}{2} = 2015028</math>. The remainder when <math>S</math> is divided by <math>1000</math> is <math>\boxed{28}</math>. | ||
+ | |||
+ | ==See Also== | ||
+ | {{iTest box|year=2007|num-b=28|num-a=30}} | ||
+ | |||
+ | [[Category:Introductory Algebra Problems]] |
Latest revision as of 18:16, 10 June 2018
Problem
Let be equal to the sum . Find the remainder when is divided by .
Solution
The list of numbers is an arithmetic sequence with terms, first term , and last term . Using the arithmetic series sum formula, . The remainder when is divided by is .
See Also
2007 iTest (Problems, Answer Key) | ||
Preceded by: Problem 28 |
Followed by: Problem 30 | |
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