Difference between revisions of "2019 AMC 8 Problems/Problem 25"
m |
m |
||
| Line 6: | Line 6: | ||
==See Also== | ==See Also== | ||
| − | {{AMC8 box|year=2019|num-b=24| | + | {{AMC8 box|year=2019|num-b=24|Last Problem}} |
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 09:53, 20 November 2019
Problem 25
Alice has 
apples. In how many ways can she share them with Becky and Chris so that each of the people has at least 
apples?
Solution 1
Using Stars and bars, and removing 
apples so each person can have , we get the total number of ways, which is 
, which is equal to 
. ~~SmileKat32
See Also
| 2019 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 24 |
Followed by [[2019 AMC 8 Problems/Problem {{{num-a}}}|Problem {{{num-a}}}]] | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
