Difference between revisions of "2010 AMC 12A Problems/Problem 1"
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== Solution == | == Solution == | ||
<math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>. | <math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>. | ||
+ | |||
+ | == Video Solution == | ||
+ | https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_ | ||
== See Also == | == See Also == |
Revision as of 09:50, 18 September 2024
Contents
Problem
What is ?
Solution
.
Video Solution
https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_
See Also
2010 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by First Problem |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.