Difference between revisions of "2018 AMC 10B Problems/Problem 1"
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== Solution 1 == | == Solution 1 == | ||
| − | The area of the pan is <math>20\cdot18=360</math>. Since the area of each piece is <math>4</math>, there are <math>\frac{360}{4} = \boxed{\textbf{(A) } 90}</math> pieces. | + | The area of the pan is <math>20\cdot18=360</math>. Since the area of each piece is <math>2\cdot2=4</math>, there are <math>\frac{360}{4} = \boxed{\textbf{(A) } 90}</math> pieces. |
== Solution 2 == | == Solution 2 == | ||
Revision as of 08:58, 20 October 2021
- The following problem is from both the 2018 AMC 12B #1 and 2018 AMC 10B #1, so both problems redirect to this page.
Problem
Kate bakes a 
-inch by 
-inch pan of cornbread. The cornbread is cut into pieces that measure 
inches by inches. How many pieces of cornbread does the pan contain?
Solution 1
The area of the pan is 
. Since the area of each piece is 
, there are 
pieces.
Solution 2
By dividing each of the dimensions by , we get a 
grid that makes 
pieces.
Video Solution
~savannahsolver
See Also
| 2018 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2018 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
