Difference between revisions of "2019 AMC 8 Problems/Problem 3"
(→Video Solution 3) |
(→Video Solution (CREATIVE THINKING!!!)) |
||
Line 59: | Line 59: | ||
~Education, the Study of Everything | ~Education, the Study of Everything | ||
+ | |||
+ | ====Video Solution by The Power of Logic(Problem 1 to 25 Full Solution)== | ||
+ | https://youtu.be/Xm4ZGND9WoY | ||
+ | |||
+ | ~Hayabusa1 | ||
==See also== | ==See also== |
Revision as of 19:46, 6 August 2023
Contents
- 1 Problem 3
- 2 Solution 1 (Bashing)
- 3 Solution 2
- 4 Solution 3 (probably won't use this solution)
- 5 Solution 4
- 6 Solution 5 -SweetMango77
- 7 Solution 6
- 8 Video Solution
- 9 Video Solution 2
- 10 Video Solution 3
- 11 Video Solution (CREATIVE THINKING!!!)
- 12 ==Video Solution by The Power of Logic(Problem 1 to 25 Full Solution)
- 13 See also
Problem 3
Which of the following is the correct order of the fractions and
from least to greatest?
Solution 1 (Bashing)
We take a common denominator:
Since it follows that the answer is
.
-xMidnightFirex
~ dolphin7 - I took your idea and made it an explanation.
- Clearness by doulai1
Solution 2
When and
,
. Hence, the answer is
.
~ ryjs
This is also similar to Problem 20 on the 2012 AMC 8.
Solution 3 (probably won't use this solution)
We use our insane mental calculator to find out that ,
, and
. Thus, our answer is
.
~~ by an insane math guy. ~~ random text that is here to distract you.
Solution 4
Suppose each fraction is expressed with denominator :
. Clearly
so the answer is
.
- Note: Duplicate of Solution 1
Solution 5 -SweetMango77
We notice that each of these fraction's numerator denominator
. If we take each of the fractions, and subtract
from each, we get
,
, and
. These are easy to order because the numerators are the same, we get
. Because it is a subtraction by a constant, in order to order them, we keep the inequality signs to get
.
Solution 6
Adding on to Solution 5, we can turn each of the fractions ,
, and
into
,
, and
, respectively. We now subtract
from each to get
,
, and
. Since their numerators are all 4, this is easy because we know that
and therefore
. Reverting them back to their original fractions, we can now see that the answer is
.
~by ChipmunkT
Video Solution
The Learning Royal: https://youtu.be/IiFFDDITE6Q
Video Solution 2
Solution detailing how to solve the problem: https://www.youtube.com/watch?v=q27qEcr7TbQ&list=PLbhMrFqoXXwmwbk2CWeYOYPRbGtmdPUhL&index=4
Video Solution 3
~savannahsolver
Video Solution (CREATIVE THINKING!!!)
~Education, the Study of Everything
==Video Solution by The Power of Logic(Problem 1 to 25 Full Solution)
~Hayabusa1
See also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.
The butterfly method is a method when you multiply the denominator of the second fraction and multiply it by the numerator from the first fraction.