Difference between revisions of "2019 AMC 8 Problems/Problem 10"
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<math>\textbf{(A) }</math>The mean increases by <math>1</math> and the median does not change. | <math>\textbf{(A) }</math>The mean increases by <math>1</math> and the median does not change. | ||
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<math>\textbf{(B) }</math>The mean increases by <math>1</math> and the median increases by <math>1</math>. | <math>\textbf{(B) }</math>The mean increases by <math>1</math> and the median increases by <math>1</math>. | ||
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<math>\textbf{(C) }</math>The mean increases by <math>1</math> and the median increases by <math>5</math>. | <math>\textbf{(C) }</math>The mean increases by <math>1</math> and the median increases by <math>5</math>. | ||
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<math>\textbf{(D) }</math>The mean increases by <math>5</math> and the median increases by <math>1</math>. | <math>\textbf{(D) }</math>The mean increases by <math>5</math> and the median increases by <math>1</math>. | ||
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<math>\textbf{(E) }</math>The mean increases by <math>5</math> and the median increases by <math>5</math>. | <math>\textbf{(E) }</math>The mean increases by <math>5</math> and the median increases by <math>5</math>. | ||
Revision as of 18:54, 20 November 2019
Problem 10
The diagram shows the number of students at soccer practice each weekday during last wee. After computing the mean and median vlaues, Coach discovers that there were actually participants on Wednesday. Which of the following statements describes the change in the mean and median after the correction is made?
The mean increases by
and the median does not change.
The mean increases by
and the median increases by
.
The mean increases by
and the median increases by
.
The mean increases by
and the median increases by
.
The mean increases by
and the median increases by
.
Solution 1
See Also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.