Difference between revisions of "2019 AMC 8 Problems/Problem 8"
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− | After Gilda gives <math>20 | + | After Gilda gives <math>20</math>% of the marbles to Pedro, she has <math>80%</math> of the marbles left. If she then gives <math>10</math>% of what's left to Ebony, she has <math>(0.8*0.9)</math> = <math>72</math>% of what she had at the beginning. Finally, she gives <math>25</math>% of what's left to her brother, so she has <math>(0.75*0.72)</math> <math>\boxed{\textbf{(E)}\ 54}</math>. of what she had in the beginning left.~heeeeeeeheeeeee |
==Solution 2== | ==Solution 2== |
Revision as of 11:48, 21 November 2019
Contents
Problem 8
Gilda has a bag of marbles. She gives of them to her friend Pedro. Then Gilda gives of what is left to another friend, Ebony. Finally, Gilda gives of what is now left in the bag to her brother Jimmy. What percentage of her original bag of marbles does Gilda have left for herself?
Solution 1
After Gilda gives % of the marbles to Pedro, she has $80%$ (Error compiling LaTeX. Unknown error_msg) of the marbles left. If she then gives % of what's left to Ebony, she has = % of what she had at the beginning. Finally, she gives % of what's left to her brother, so she has . of what she had in the beginning left.~heeeeeeeheeeeee
Solution 2
Suppose Gilda has 100 marbles.
Then she gives Pedro 20% of 100 = 20, she remains with 80 marbles.
Out of 80 marbles she gives 10% of 80 = 8 to Ebony.
Thus she remains with 72 marbles.
Then she gives 25% of 72 = 18 to Jimmy, finally leaving her with 54.
And = 54% =
~phoenixfire
See Also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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