Difference between revisions of "2018 AMC 10B Problems/Problem 2"
MRENTHUSIASM (talk | contribs) m (→Solution 2) |
(→Video Solution) |
||
Line 32: | Line 32: | ||
\end{align*}</cmath> | \end{align*}</cmath> | ||
~coolmath_2018 ~MRENTHUSIASM | ~coolmath_2018 ~MRENTHUSIASM | ||
+ | |||
+ | ==Video Solution (HOW TO THINK CRITICALLY!!!)== | ||
+ | https://youtu.be/VN88m4xUHM0 | ||
+ | |||
+ | ~Education, the Study of Everything | ||
+ | |||
+ | |||
== Video Solution == | == Video Solution == | ||
https://youtu.be/77dDIzKprzA | https://youtu.be/77dDIzKprzA | ||
− | |||
− | |||
==See Also== | ==See Also== |
Revision as of 21:08, 27 May 2023
- The following problem is from both the 2018 AMC 12B #2 and 2018 AMC 10B #2, so both problems redirect to this page.
Contents
Problem
Sam drove miles in minutes. His average speed during the first minutes was mph (miles per hour), and his average speed during the second minutes was mph. What was his average speed, in mph, during the last minutes?
Solution 1
Suppose that Sam's average speed during the last minutes was mph.
Recall that a half hour is equal to minutes. Therefore, Sam drove miles during the first half hour, miles during the second half hour, and miles during the last half hour. We have ~Haha0201 ~MRENTHUSIASM
Solution 2
Suppose that Sam's average speed during the last minutes was mph.
Note that Sam's average speed during the entire trip was mph. Since Sam drove at mph, mph, and mph for the same duration ( minutes each), his average speed during the entire trip was the average of mph, mph, and mph. We have ~coolmath_2018 ~MRENTHUSIASM
Video Solution (HOW TO THINK CRITICALLY!!!)
~Education, the Study of Everything
Video Solution
See Also
2018 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2018 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.