Difference between revisions of "2010 AMC 12A Problems/Problem 1"

Latest revision as of 10:53, 18 September 2024

What is $\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)$ ?

$\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 401 \qquad \textbf{(E)}\ 4020$

$20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}$ .

~Charles3829

2010 AMC 12A (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
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All AMC 12 Problems and Solutions

@@ Line 7: / Line 7: @@
 <math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>.
-== Video Solution ==
+==Video Solution==
 https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_
+~Charles3829
 == See Also ==