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Difference between revisions of "2018 AMC 10B Problems/Problem 24"

(→‎Solution)
(→‎Solution)
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E=(0,sqrt(3));
 
E=(0,sqrt(3));
 
F=(-1/2,sqrt(3)/2);
 
F=(-1/2,sqrt(3)/2);
−
W=(4/3,2sqrt(3)/3);
+
 
−
X=(4/3,sqrt(3)/3);
 
−
Y=(-1/3,sqrt(3)/3);
 
−
Z=(-1/3,2sqrt(3)/3);
 
 
draw(A--B--C--D--E--F--cycle);
 
draw(A--B--C--D--E--F--cycle);
−
draw(W--Z);
+
 
−
draw(X--Y);
 
 
draw(F--C--B--E--D--A);
 
draw(F--C--B--E--D--A);
  
Line 33: Line 29:
 
label("$E$",E,NW);
 
label("$E$",E,NW);
 
label("$F$",F,WSW);
 
label("$F$",F,WSW);
−
label("$W$",W,ENE);
+
 
−
label("$X$",X,ESE);
 
−
label("$Y$",Y,WSW);
 
−
label("$Z$",Z,WNW);
 
 
</asy>
 
</asy>
  

Revision as of 16:29, 16 February 2018

Problem

Let $ABCDEF$ be a regular hexagon with side length $1$. Denote $X$, $Y$, and $Z$ the midpoints of sides $\overline {AB}$, $\overline{CD}$, and $\overline{EF}$, respectively. What is the area of the convex hexagon whose interior is the intersection of the interiors of $\triangle ACE$ and $\triangle XYZ$?

$\textbf{(A)} \frac {3}{8}\sqrt{3} \qquad \textbf{(B)} \frac {7}{16}\sqrt{3} \qquad \textbf{(C)} \frac {15}{32}\sqrt{3} \qquad \textbf{(D)} \frac {1}{2}\sqrt{3} \qquad \textbf{(E)} \frac {9}{16}\sqrt{3} \qquad$


Answer: $\frac {15}{32}\sqrt{3}$

Solution

[asy] pair A,B,C,D,E,F,W,X,Y,Z; A=(0,0); B=(1,0); C=(3/2,sqrt(3)/2); D=(1,sqrt(3)); E=(0,sqrt(3)); F=(-1/2,sqrt(3)/2); draw(A--B--C--D--E--F--cycle); draw(F--C--B--E--D--A); label("$A$",A,SW); label("$B$",B,SE); label("$C$",C,ESE); label("$D$",D,NE); label("$E$",E,NW); label("$F$",F,WSW); [/asy]

See Also

2018 AMC 10B (Problems • Answer Key • Resources)
Preceded by
Problem 23 		Followed by
Problem 25
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions
2018 AMC 12B (Problems • Answer Key • Resources)
Preceded by
Problem 19 		Followed by
Problem 21
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 12 Problems and Solutions

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