Difference between revisions of "2018 AMC 10B Problems/Problem 24"
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X=(1/2, sqrt(3)); | X=(1/2, sqrt(3)); | ||
Y=(5/4, sqrt(3)/4); | Y=(5/4, sqrt(3)/4); | ||
| − | Z=(-1/ | + | Z=(-1/4, sqrt(3)/4); |
draw(A--B--C--D--E--F--cycle); | draw(A--B--C--D--E--F--cycle); | ||
| − | draw(A--C--E); | + | draw(A--C--E--cylce); |
| − | draw(X--Y--Z); | + | draw(X--Y--Z--cycle); |
label("$A$",A,NW); | label("$A$",A,NW); | ||
Revision as of 17:35, 16 February 2018
Problem
Let 
be a regular hexagon with side length 
. Denote 
, 
, and 
the midpoints of sides 
, 
, and 
, respectively. What is the area of the convex hexagon whose interior is the intersection of the interiors of 
and 
?
Answer: 
Solution
![[asy] pair A,B,C,D,E,F,W,X,Y,Z; A=(0,sqrt(3)); B=(1,sqrt(3)); C=(3/2,sqrt(3)/2); D=(1,0); E=(0,0); F=(-1/2,sqrt(3)/2); X=(1/2, sqrt(3)); Y=(5/4, sqrt(3)/4); Z=(-1/4, sqrt(3)/4); draw(A--B--C--D--E--F--cycle); draw(A--C--E--cylce); draw(X--Y--Z--cycle); label("$A$",A,NW); label("$B$",B,NE); label("$C$",C,ESE); label("$D$",D,SE); label("$E$",E,SW); label("$F$",F,WSW); label("$X$", X, N); label("$Y$", Y, ESE); label("$Z$", Z, WSW); [/asy]](http://latex.artofproblemsolving.com/d/1/1/d11689bcd45191ec4f123485151c9a53cc9b2905.png)
See Also
| 2018 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2018 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 19 |
Followed by Problem 21 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
