2019 AMC 8 Problems/Problem 19
Solution 3
We can name the top three teams as and
. We can see that
, because these teams have the same points. If we look at the matches that involve the top three teams, we see that there are some duplicates:
and
come twice. In order to even out the scores and get the maximum score, we can say that in match
and
each win once out of the two games that they play. We can say the same thing for
and
. This tells us that each team
and
win and lose twice. This gives each team a total of 3 + 3 + 0 + 0 = 6 points. Now, we need to include the other three teams. We can label these teams as
and
. We can write down every match that
or
plays in that we haven't counted yet:
and
. We can say
and
win each of these in order to obtain the maximum score that
and
can have. If
and
win all six of their matches,
and
will have a score of
.
results in a maximum score of
. This tells us that the correct answer choice is
.
~Champion1234
Video Solutions
Associated Video - https://youtu.be/s0O3_uXZrOI
Video Solution - https://youtu.be/Lw8fSbX_8FU (Also explains problems 11-20)
See Also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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