2021 AMC 12A Problems/Problem 9
Contents
Problem
These problems will not be posted until the 2021 AMC12A is released on Thursday, February 4, 2021.
Solution
Expanding, we get that the expression is 
or 
. By the trivial inequality(all squares are nonnegative) the minimum value for this is 
, which can be achieved at 
. ~aop2014
Note
See problem 1.
See also
| 2021 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 8 |
Followed by Problem 10 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
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