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• 2005 CEMC Gauss (Grade 7) Problems/Problem 15
  ...>T</math> is halfway between <math>Q</math> and <math>R</math>, then <math>V</math> is halfway between <math>P</math> and <math>S</math>. Therefore, <m
  2 KB (349 words) - 02:41, 23 October 2014
• 1987 AHSME Problems/Problem 16
  <math>\{V, W, X, Y, Z\}</math>. Using this correspondence, the cryptographer finds th ...to <math>0</math>, <math>3</math>, and <math>4</math>), we must have <math>V = 2</math> and <math>Y = 1</math>. Thus <math>XYZ = 413_{5} = 4 \cdot 5^{2}
  2 KB (242 words) - 14:32, 1 March 2018
• 2015 AMC 10A Problems/Problem 23
  ...pairs (not counting transpositions because this does not affect (<math>u + v</math>), <math>(2, 8), (4, 4), (-2, -8), (-4, -4)</math>, yields <math>a =
  2 KB (372 words) - 00:28, 27 September 2021
• 2015 AMC 10A Problems/Problem 21
  ...dron and <math>TD</math> as the height. Thus, the desired volume is <cmath>V = \dfrac{1}{3} bh = \dfrac{1}{3}\cdot[ABC]\cdot TD = \dfrac{1}{3} \cdot 6 \ <cmath>V = \dfrac{1}{3} Bh = \dfrac{1}{3} h \cdot BE \cdot \dfrac{6\sqrt{2}}{5} = \d
  4 KB (689 words) - 20:16, 18 June 2024
• 2015 AMC 10A Problems/Problem 3
  path h = ellipse((0.5,0),0.45,0.015), v = ellipse((0,0.5),0.015,0.45); filldraw(shift((j,i))*v,black);
  2 KB (393 words) - 03:20, 1 June 2024
• 2015 AIME I Problems/Problem 10
  ...>a\neq 0</math> (else <math>f</math> is not cubic) where <math>\{q,r,s,t,u,v\}</math> is the same as the set <math>\{1,2,3,5,6,7\}</math>. Subtracting t <cmath>24=a((t+u+v-(q+r+s))x^2-a(tu+uv+tv-(qr+qs+rs))x+a(tuv-qrs)</cmath>
  8 KB (1,474 words) - 10:00, 10 November 2023
• 2015 AIME II Problems
  ...he volume of water thus displaced is <math>v</math> cubic feet. Find <math>v^2</math>.
  8 KB (1,326 words) - 19:15, 13 January 2024
• 2015 AIME II Problems/Problem 9
  ...he volume of water thus displaced is <math>v</math> cubic feet. Find <math>v^2</math>. <cmath>v = \frac{1}{3}(2\sqrt{6})\left(\frac{1}{2} \cdot (2\sqrt{6})^2\right) = \fra
  7 KB (1,074 words) - 01:49, 22 January 2024
• 2015 USAMO Problems/Problem 2
  Let <math>M=(u,v)</math>, then <math>T=(2u+\cos(2A), 2v-\sin(2A))</math>. ...cos(2A))^2+ (2v-\sin(2A))^2=1</math>, namely <math>v\sin(2A)-u\cos(2A)=u^2+v^2</math>. (E2)
  5 KB (902 words) - 09:58, 20 August 2021
• 2015 USAJMO Problems/Problem 3
  Let <math>M=(u,v)</math>, then <math>T=(2u+\cos(2A), 2v-\sin(2A))</math>. ...cos(2A))^2+ (2v-\sin(2A))^2=1</math>, namely <math>v\sin(2A)-u\cos(2A)=u^2+v^2</math>. (E2)
  4 KB (760 words) - 16:45, 29 April 2020
• Aops font
  | <span class="aops-font">V</span> | V
  6 KB (924 words) - 21:31, 22 February 2024
• 2015 AMC 8 Problems/Problem 17
  For starters, we identify d as distance and v as velocity (speed) ...equation gives us: <math>\frac{d}{v}=\frac{1}{3}</math> and <math>\frac{d}{v+18}=\frac{1}{5}</math>.
  4 KB (608 words) - 17:05, 17 January 2024
• 2016 AMC 12B Problems/Problem 8
  ...e, we can set up a proportion based on the principle that <math>d=\frac{m}{V}</math>, thus <math>dV=m</math>.
  2 KB (325 words) - 14:21, 19 January 2021
• Gmaas
  231. Gmaas once demanded Epic Games to give him 5,000,000 V-bucks for his 569823rd birthday. EDIT: This is why Gmaas no longer has an E
  69 KB (11,805 words) - 20:49, 18 December 2019
• 2016 USAJMO Problems/Problem 1
  pair V = incenter(A,C,P); dot("$I_C$", V, NW);
  5 KB (1,004 words) - 15:15, 28 June 2020
• 2016 USAMO Problems/Problem 3
  <math>V</math> is the foot ot perpendicular from <math>O</math> to <math>AI_A.</mat
  6 KB (998 words) - 21:36, 17 October 2022
• 1983 AHSME Problems/Problem 29
  ...</math> to <math>A, B</math> and <math>C</math>, respectively, be <math>u, v</math> and <math>w</math>. ...est distance that <math>P</math> can be from <math>D</math> if <math>u^2 + v^2 = w^2</math>?
  1 KB (255 words) - 01:11, 20 February 2019
• Mock AIME 4 Pre 2005/Problems
  ...<math>\overline{MS}</math> intersects <math>\overline{OP}</math> at <math>V</math> . If <math>AB = 2,</math> <math>BC = 2005,</math> <math>CD = 4,</mat
  7 KB (1,094 words) - 15:39, 24 March 2019
• Mock AIME 3 2010 Problems
  r, s, t, u, v, w, x, y, and z such that n + l + v − y = 0
  14 KB (2,904 words) - 18:24, 16 May 2017
• 2017 AMC 12A Problems/Problem 25
  The vertices <math>V</math> of a centrally symmetric hexagon in the complex plane are given by <cmath>V=\left\{ \sqrt{2}i,-\sqrt{2}i, \frac{1}{\sqrt{8}}(1+i),\frac{1}{\sqrt{8}}(
  18 KB (2,878 words) - 01:47, 16 December 2023

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